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3 years ago

5

Jacob obtained a 15-year, $245,900 for his new vacation home. The interest rate is 5.5% and his monthly payment is $2,009.21. Fo

r the first payment, find the new balance to the nearest cent.

1 answer:

Blizzard [7]3 years ago

3 0

He would pay $2119.72 and his remaing balance would be $243,780.28

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Kaylee invested $910 in an account paying an interest rate of 2.6% compounded

Nikitich [7]

Answer:

$1,179

Step-by-step explanation:

Lets use the compound interest formula provided to solve this:

$A=P(1+\frac{r}{n} )^{nt}$

<em>P = initial balance</em>

<em>r = interest rate (decimal)</em>

<em>n = number of times compounded annually</em>

<em>t = time</em>

<em />

First, lets change 2.6% into a decimal:

2.6% -> $\frac{2.6}{100}$ -> 0.026

Since the interest is compounded quarterly, we will use 4 for n. Lets plug in the values now:

$A=910(1+\frac{0.026}{4})^{4(10)}$

$A=1,179.21$

The account balance after 10 years will be $1,179

8 0

3 years ago

Solve Highschool Pre cal

Bezzdna [24]

Option C:

$\ln 64 y^{2}$

Solution:

Given expression: 2 ln 8 + 2 ln y

Applying log rule $a \log b=\log b^{a}$ in the above expression.

⇒ $2 \ln 8+2 \ln y=\ln 8^{2}+\ln y^{2}$

Applying log rule $\log a+\log b=\log (a b)$ in the above expression.

⇒ $\ln 8^{2}+\ln y^{2}=\ln \left(8^{2} y^{2}\right)$

We know that $8^{2}=64$

⇒ $\ln \left(8^{2} y^{2}\right)=\ln 64 y^{2}$

Hence, the expression in single natural logarithm is $\ln 64 y^{2}$ .

6 0

3 years ago

What is the solution to the following equation? 3(X - 4)- 5 = X - 3 O A. X = 12 B. X = 8 O C. x=7 O D. *= 3

Andrews [41]

Answer: c.) x = 7

Step-by-step explanation:

6 0

3 years ago

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Solve the initial value problem: y'(x)=(4y(x)+25)^(1/2) ,y(1)=6. you can't really tell, but the '1/2' is the exponent

goblinko [34]

Answer:

$y(x)=x^2+5x$

Step-by-step explanation:

Given: $y'=\sqrt{4y+25}$

Initial value: y(1)=6

Let $y'=\dfrac{dy}{dx}$

$\dfrac{dy}{dx}=\sqrt{4y+25}$

Variable separable

$\dfrac{dy}{\sqrt{4y+25}}=dx$

Integrate both sides

$\int \dfrac{dy}{\sqrt{4y+25}}=\int dx$

$\sqrt{4y+25}=2x+C$

Initial condition, y(1)=6

$\sqrt{4\cdot 6+25}=2\cdot 1+C$

$C=5$

Put C into equation

Solution:

$\sqrt{4y+25}=2x+5$

or

$4y+25=(2x+5)^2$

$y(x)=\dfrac{1}{4}(2x+5)^2-\dfrac{25}{4}$

$y(x)=x^2+5x$

Hence, The solution is $y(x)=\dfrac{1}{4}(2x+5)^2-\dfrac{25}{4}$ or $y(x)=x^2+5x$

4 0

3 years ago

Melissa read 4 books each week for 4 weeks. Amanda read 5 books a week for 4 weeks. How many more books did Amanda read?

yarga [219]

Amanda read 4 more books then Melissa.

3 0

3 years ago

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