Substitute the numbers in the equation:
Since L=5in, W=4in and H=8in:
Therefore, the volume is equal to 160 inches cubed.
Y=mx
m=amount of time per day studied
y=time
x=number of days
we have
60=m(4)
divide by 4
15=m
y=15x
Answer:
Step-by-step explanation:
Let X is the number of cards Kenny has
Let Y is the number of cards Lee has
1. Kenny had 5/7 more trading cards than lee, it means
X = Y + 5/7X (1)
2. After Kenny collected 50% more trading cards, he had 220 more trading cards than lee, it means:
X + 50%X = Y + 220 (2)
So, we solve the 2 equations to find out X and Y
<=> X = 
and Y = 
<=> X ≈181 and Y ≈ 52
Given that the first number shows up as four. The second number should be six so that the sum would be ten. Therefore, its probability should be 1/6.
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Here we must see in how many different ways we can select 2 students from the 3 clubs, such that the students <em>do not belong to the same club. </em>We will see that there are 110 different ways in which 2 students from different clubs can be selected.
So there are 3 clubs:
- Club A, with 10 students.
- Club B, with 4 students.
- Club C, with 5 students.
The possible combinations of 2 students from different clubs are
- Club A with club B
- Club A with club C
- Club B with club C.
The number of combinations for each of these is given by the product between the number of students in the club, so we get:
- Club A with club B: 10*4 = 40
- Club A with club C: 10*5 = 50
- Club B with club C. 4*5 = 20
For a total of 40 + 50 + 20 = 110 different combinations.
This means that there are 110 different ways in which 2 students from different clubs can be selected.
If you want to learn more about combination and selections, you can read:
brainly.com/question/251701
