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Romashka-Z-Leto [24]
4 years ago
13

Translate into an algebraic expression: How much 50% sugar syrup can you make if you have x grams of sugar ?

Mathematics
1 answer:
makkiz [27]4 years ago
4 0

Answer:

The algebraic expression is v = 2x

v is the volume of the sugar syrup and

x is the mass of sugar in grams.

Step-by-step explanation:

Let x be the mass of sugar in grams and v be the volume of sugar syrup.

So, mass of sugar in grams/volume of sugar syrup × 100 % = 50 %

x/v × 100 % = 50 %

x/v = 50/100

x/v = 1/2

v = 2x

So, the algebraic expression required is v = 2x where v is the volume of the sugar syrup and x is the mass of sugar in grams.

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Solve the problem 3g+7g+8=-10+g
Vinil7 [7]
First simplify like terms (things with the same letter):

3g + 7g + 8 = -10 + g

10g + 8 = -10 + g

Next we should take g off both sides:

9g + 8 = -10

Next isolate 9g by taking 8 off both sides:

9g = -18

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3 0
3 years ago
Pleaseee help me I’m lost
mestny [16]

Answer:

10x^3+14x^2-25x-35

Step-by-step explanation:

f(x) = 2x^2 -5

g(x)= 5x+7

f(g(x)) = (2x^2 -5)(5x+7)

5x(2x^2 -5)+7(2x^2 -5)

10x^3-25x+14x^2-35

10x^3+14x^2-25x-35

8 0
3 years ago
Which of the following is an even function g(x) = (x – 1)2 + 1g(x) = 2x2 + 1g(x) = 4x + 2g(x) = 2x
GuDViN [60]
An even function can be reflected about the y axis and map onto itself
example: y=x^2

an odd function can be reflected about the origin and map onto itself
example: y=x^3


a simple test is the following

if f(x) is even then f(-x)=f(x)
if f(x) is odd then f(-x)=-f(x)


so

even function
subsitute -x for each and see if we get the same function
remember to fully expand these

g(x)=(x-1)^2+1=x^2-2x+1+1=x^2-2x+2 is the original one

g(x)=(x-1)^2+1
g(-x)=(-x-1)^2+1
g(-x)=(1)(x+1)^2+1
g(-x)=x^2+2x+1+1
g(-x)=x^2+2x+2
not same because the original has -2x
not even


g(x)=2x^2+1
g(-x)=2(-x)^2+1
g(-x)=2x^2+1
same, it's even

g(x)=4x+2
g(-x)=4(-x)+2
g(-x)=-4x+2
not the same, not even

g(x)=2x
g(-x)=2(-x)
g(-x)=-2x
not same, not even



g(x)=2x²+1 is the even function
8 0
3 years ago
Read 2 more answers
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