The transformation that mapped ∆ABC onto ∆A′B′C′ is a reflection over the x-axis. The coordinate of B'' would be same as that of B'.
<h3>How to solve transformation problems? </h3>
We are given the coordinates as;
∆ABC; A(-6, 2), B(-2, 6), C(-4, 2).
∆A′B′C; A'(-6, - 2), B (-2, -6), C (-4, -2).
A) Now, we are told that ∆ABC was transformed to
∆A′B′C. From the given coordinates, we see that only the y coordinate sign changed after the transformation. Thus, the transformation that mapped ∆ABC onto ∆A′B′C′ is a reflection over the x-axis.
B) Now, ∆A′B′C′ is reflected across the line x = -2 to form ∆A″B″C″. Since the line x = -2 is vertical and the coordinate of B' in ∆A′B′C′ has an x - coordinate of -2, then it means the coordinate of B'' would be same as that of B'
Read more about transformations at; brainly.com/question/4289712
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