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3 years ago

Mike needs to paint several rooms in his house. He knows that the larger the rooms are, the more paint he will need.

1 answer:

soldier1979 [14.2K]3 years ago

6 0

Yes, you are absolutely correct. It seems like Mike knows that paint and the size of the rooms are directly proportional i.e., the larger the size of the room, the more paint it requires. Mike is smart.

If this is what you are looking for.

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The process standard deviation is 0.27, and the process control is set at plus or minus one standard deviation. Units with weigh

mr_godi [17]

Answer:

a) $P(X$

And for the other case:

tex] P(X>10.15)[/tex]

$P(X>10.15)= P(Z > \frac{10.15-10}{0.15}) = P(Z>1)=1-P(Z$

So then the probability of being defective P(D) is given by:

$P(D) = 0.159+0.159 = 0.318$

And the expected number of defective in a sample of 1000 units are:

$X= 0.318*1000= 318$

b) $P(X$

And for the other case:

tex] P(X>10.15)[/tex]

$P(X>10.15)= P(Z > \frac{10.15-10}{0.05}) = P(Z>3)=1-P(Z$

So then the probability of being defective P(D) is given by:

$P(D) = 0.00135+0.00135 = 0.0027$

And the expected number of defective in a sample of 1000 units are:

$X= 0.0027*1000= 2.7$

c) For this case the advantage is that we have less items that will be classified as defective

Step-by-step explanation:

Assuming this complete question: "Motorola used the normal distribution to determine the probability of defects and the number of defects expected in a production process. Assume a production process produces items with a mean weight of 10 ounces. Calculate the probability of a defect and the expected number of defects for a 1000-unit production run in the following situation.

Part a

The process standard deviation is .15, and the process control is set at plus or minus one standard deviation. Units with weights less than 9.85 or greater than 10.15 ounces will be classified as defects."

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution to the problem

Let X the random variable that represent the weights of a population, and for this case we know the distribution for X is given by:

$X \sim N(10,0.15)$

Where $\mu=10$ and $\sigma=0.15$

We can calculate the probability of being defective like this:

$P(X$

And we can use the z score formula given by:

$z=\frac{x-\mu}{\sigma}$

And if we replace we got:

$P(X$

And for the other case:

tex] P(X>10.15)[/tex]

$P(X>10.15)= P(Z > \frac{10.15-10}{0.15}) = P(Z>1)=1-P(Z$

So then the probability of being defective P(D) is given by:

$P(D) = 0.159+0.159 = 0.318$

And the expected number of defective in a sample of 1000 units are:

$X= 0.318*1000= 318$

Part b

Through process design improvements, the process standard deviation can be reduced to .05. Assume the process control remains the same, with weights less than 9.85 or greater than 10.15 ounces being classified as defects.

$P(X$

And for the other case:

tex] P(X>10.15)[/tex]

$P(X>10.15)= P(Z > \frac{10.15-10}{0.05}) = P(Z>3)=1-P(Z$

So then the probability of being defective P(D) is given by:

$P(D) = 0.00135+0.00135 = 0.0027$

And the expected number of defective in a sample of 1000 units are:

$X= 0.0027*1000= 2.7$

Part c What is the advantage of reducing process variation, thereby causing process control limits to be at a greater number of standard deviations from the mean?

For this case the advantage is that we have less items that will be classified as defective

5 0

3 years ago

Natalia begins to find the mean absolute deviation of this data set. She finds the mean of the data and then finds the distance

s2008m [1.1K]

Hello!

To calculate mean absolute deviation, you find the mean, find the distance between each data point and the mean, add up those distances, and divide by the number of data points.

In this scenario, after Natalia finds the distances, she must add them all up and then divide by the number of data points.

I hope this helps!

3 0

3 years ago

Read 2 more answers

Can someone help me find the answer?

raketka [301]

Answer:

AC=9 cm

ABC is not a right angled triangle

Step-by-step explanation:

AB=8cm

BC=5cm

22=AB+BC+AC

AC=22-8-5

AC=9

since AC is the longest,

using Pythagoras theorem

AC^2=BC^2+AB^2

9^2=8^2+5^2

81=64+25

81=89

therefore, it is not a right angled triangle

8 0

3 years ago

Read 2 more answers

Find the mean 3,4,4,2,5,7,2

stich3 [128]

Thats 3.85714285714 because if you add the numbers and divide by the numbers they are it’ll be 3.85714285714

7 0

3 years ago

This is just for fun, but I still need to figure this out

Vilka [71]

Answer:

Let them defrost first, then heat them up for a couple of minutes in the toaster.

Step-by-step explanation:

7 0

3 years ago