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tankabanditka [31]
2 years ago
11

The surface area of one cube is twice the surface area of a second cube.

Mathematics
1 answer:
Usimov [2.4K]2 years ago
4 0

Answer:

2\sqrt{2} :1

Step-by-step explanation:

This question was linked from another one regarding the lengths of the cubes, you can find it here: brainly.com/question/22396279

That question gave you the ratio of the lengths, which is \sqrt{2} :1. Now in geometry, a general rule about solids is that if they are similar, the ratio of their volumes is the cube of the ratio of their edges. In a cube's case, every single cube known to mankind is similar as all the edges are the same length.

So the ratio of volumes would be \sqrt{2} ^3:1^3, which can be simplified as 2\sqrt{2} :1.

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Answer:

the answer is E, right?

Step-by-step explanation:

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A mountain peak is 12,200 feet above sea level. The valley below is 218 feet below sea level. How far is it from the peak to the
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A mapping diagram showing a relation, using arrows, between input and output for the following ordered pairs: (negative 3, negat
il63 [147K]

Answer:

  {x | x = –5, –3, 1, 2, 6}

Step-by-step explanation:

The domain is the list of first-values of the ordered pairs:

   {x | x = –5, –3, 1, 2, 6}

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If cos(x) = Three-fourths and tan(x) < 0, what is cos(2x)?
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Step-by-step explanation:

The value of sin(2x) is \sin(2x) = - \frac{\sqrt{15}}{8}sin(2x)=−

8

15

How to determine the value of sin(2x)

The cosine ratio is given as:

\cos(x) = -\frac 14cos(x)=−

4

1

Calculate sine(x) using the following identity equation

\sin^2(x) + \cos^2(x) = 1sin

2

(x)+cos

2

(x)=1

So we have:

\sin^2(x) + (1/4)^2 = 1sin

2

(x)+(1/4)

2

=1

\sin^2(x) + 1/16= 1sin

2

(x)+1/16=1

Subtract 1/16 from both sides

\sin^2(x) = 15/16sin

2

(x)=15/16

Take the square root of both sides

\sin(x) = \pm \sqrt{15/16

Given that

tan(x) < 0

It means that:

sin(x) < 0

So, we have:

\sin(x) = -\sqrt{15/16

Simplify

\sin(x) = \sqrt{15}/4sin(x)=

15

/4

sin(2x) is then calculated as:

\sin(2x) = 2\sin(x)\cos(x)sin(2x)=2sin(x)cos(x)

So, we have:

\sin(2x) = -2 * \frac{\sqrt{15}}{4} * \frac 14sin(2x)=−2∗

4

15

∗

4

1

This gives

\sin(2x) = - \frac{\sqrt{15}}{8}sin(2x)=−

8

15

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what is the equation of a line that passes through the point (6,1) and is perpendicular to the line whose equation is y=2x-6?
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Answer:

y = -(1/2)x + 4

Step-by-step explanation:

Use the standard form on an equation:  y = mx + b

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1 = -3 + b

4 = b  

so our equation is

y = -(1/2)x + 4

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3 years ago
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