Answer:
8 maths tests
Step-by-step explanation:
Given data
We are told that in 1/4 hour that is 0.25hour (15 mins) She grades 1 math test
our aim is to find how many maths test she grade in 3 hours (120min)
Hence
in 15 mins she does 1 grading
in 120 mins she does x
cross multiply
15x= 120
divide both sides by 15
x= 120/15
x= 8 maths test
Hence in 2 hours, she can grade 8 maths tests
<h3>
Answer: 16 square units</h3>
Let x be the height of the parallelogram. Right now it's unknown, but we can solve for it using the pythagorean theorem. Focus on the right triangle. It has legs a = 3 and b = x, with hypotenuse c = 5
a^2 + b^2 = c^2
3^2 + x^2 = 5^2
9 + x^2 = 25
x^2 = 25-9
x^2 = 16
x = sqrt(16)
x = 4
This is a 3-4-5 right triangle.
The height of the parallelogram is 4 units.
We have enough info to find the area of the parallelogram
Area of parallelogram = base*height
Area of parallelogram = 4*4
Area of parallelogram = 16 square units
Coincidentally, the base and height are the same, which isn't always going to be the case. The base is visually shown as the '4' in the diagram. The height is the dashed line, which also happens to be 4 units long.
The answer is 36330 it should be at least
Answer:
m∠MON = 15°
Step-by-step explanation:
The given parameters are;
m∠LON = 77°
m∠LOM = 9·x + 44°
m∠MON = 6·x + 3°
By angle addition postulate, we have;
m∠LON = m∠LOM + m∠MON
Therefore, by substituting the known values, we have;
∴ 77° = 9·x + 44° + 6·x + 3°
77° = 9·x + 44° + 6·x + 3° = 15·x + 47°
77° = 15·x + 47°
77° - 47° = 15·x
15·x = 77° - 47° = 30°
15·x = 30°
x = 30°/15 = 2°
x = 2°
Given that m∠MON = 6·x + 3° and x = 2°, we have;
m∠MON = 6 × 2° + 3° = 12° + 3° = 15°
m∠MON = 15°.
Answer:
Step-by-step explanation:
(6u)+(-2u)=4u
(-7c)+(4c)=-3c
6=6
4u-3c+6
