The water level increases by 0.608 meters per minute when the water is 3.5 m deep
<h3>How to determine the rate?</h3>
The given parameters are:
- Radius, r = 3
- Height, h = 7
- Rate in, V' = 4.3m^3/min
The relationship between the radius and height is:
r/h = 3/7
Make r the subject
r = 3h/7
The volume of a cone is;

This gives

Expand

Differentiate

Make h' the subject

When the water level is 3.5.
We have:

Also, we have:
V' = 4.3
So, the equation becomes

Evaluate the products

Evaluate the quotient
h' = 0.608
Hence, the water level increases by 0.608 meters per minute
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Firstly make the f(x) = x and x = y:
x = y^2
Then solve for y:
√x = y
Hopefully this helps and let me know if you have more questions!
Answer:
y=3x-4
Step-by-step explanation:
Answer:
5/4
Step-by-step explanation:
Answer:
x = - 2, x = - 
Step-by-step explanation:
Given
5x² + 1 = - 13x - 5 ( add 13x - 5 to both sides )
5x² + 13x + 6 = 0
Consider the factors of the product of the x² term and the constant term which sum to give the coefficient of the x- term
product = 5 × 6 = 30 and sum = 13
The factors are 10 and 3
Use these factors to split the x- term
5x² + 10x + 3x + 6 = 0 ( factor the first/second and third/fourth terms )
5x(x + 2) + 3(x + 2) = 0 ← factor out (x + 2) from each term
(x + 2)(5x + 3) = 0
Equate each factor to zero and solve for x
x + 2 = 0 ⇒ x = - 2
5x + 3 = 0 ⇒ 5x = - 3 ⇒ x = - 