1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
stich3 [128]
3 years ago
6

Please help I have been stuck this for a while

Mathematics
1 answer:
ahrayia [7]3 years ago
7 0

Answer:

Option (D)

Step-by-step explanation:

Given expression is,

x³ × 3 ÷ \frac{2}{9} + 9x - (7 - 6x)

By substituting x = \frac{2}{3},

(\frac{2}{3})^3\times 3 \div \frac{2}{9}+9(\frac{2}{3})-[7-6(\frac{2}{3})]

By using rule PEMDAS,

P - Parenthesis

E - Exponent

M - Multiplication

D - Division

A - Addition

S - Subtraction

=(\frac{2}{3})^3\times 3 \div \frac{2}{9}+9(\frac{2}{3})-[7-4]

= (\frac{2}{3})^3\times 3 \div \frac{2}{9}+9(\frac{2}{3})-3

= \frac{8}{27}\times 3 \div \frac{2}{9}+6-3

= \frac{8}{9}\div \frac{2}{9}+6-3

= \frac{8}{9}\times \frac{9}{2}+6-3

= 4 + 6 - 3

= 7

Option (D) is the answer.

You might be interested in
According to the order of operations, what operation should be performed first in the expression 8 minus 2 times 2 divided by le
Crank

Answer:

addition

Step-by-step explanation:

in this case its addition , but the only reson it is going first is bc it sin the parenthasies

3 0
3 years ago
Read 2 more answers
Show that 0-58200-48826-5 is a valid UPC number
trasher [3.6K]
0-58200-48826-5djdjbdnd
3 0
3 years ago
The student body of a large university consists of 40% Business majors. A random sample of six students from this university is
Mashcka [7]

Answer:

The answer is 0.31

Step-by-step explanation:

We can solve this problem as a binomial distribution function. Probability of selecting business mayors is p=0.4 and selecting non-business mayors is q=0.6.

Then selecting 2 busies mayors out of six is:

P(x)=combination(6,2)*0.4^2*0.6^4\\P(x)=0.31

7 0
3 years ago
A factory produces widgets whose length must be within 1.5 mm of an ideal length of 47 mm. A factory supervisor wants to mark ru
Nat2105 [25]

Using absolute value, it is found that:

  • The situation is described by the following equation: |l - 47| = 1.5
  • The markings should be between 45.5mm and 48.5mm.

---------------------------

The definition of the <em>absolute value function</em> is as follows:

|x| = x, x \geq 0

|x| = -x, x < 0

----------------------------

The length should be set to 47mm with an allowance of 1.5mm, which means that <u>the absolute value of the difference between the length and 47 should be 1.5</u>, thus:

|l - 47| = 1.5

----------------------------

The solutions are:

l - 47 = -1.5 \rightarrow l = 45.5

l - 47 = 1.5 \rightarrow l = 48.5

The markings should be between 45.5mm and 48.5mm.

A similar problem is given at brainly.com/question/24514895

3 0
3 years ago
in an isosceles triangle, the ratio of the measure of the vertex to the meaure of a base angle is 1:4. find the meaure of the ve
cluponka [151]
The vertex angle is equal to 20 degrees.
7 0
3 years ago
Other questions:
  • 47% of 70 estimated ????? help pleazzz
    15·1 answer
  • Find the number if :<br> 5/9 of it is 90
    9·2 answers
  • Multiply<br> ( 4x + 6y ) to the power of two 2<br> what is the answer?
    7·1 answer
  • In math class, the ratio of boys to girls in the class is 12:8. What is the ratios of the total number of students to the number
    12·1 answer
  • Yo plz help I don't understand
    10·1 answer
  • What is the inverse of the function f(x) = 2x – 10?
    5·1 answer
  • A sunflower grows to be 200cm tall. After four weeks, it was 30% of this height. How tall
    13·1 answer
  • Help me quickly please, im not good at this kind of math.
    10·1 answer
  • I WILL GIVE 20 POINTS TO THOSE WHO ANSWER THIS QUESTION RIGHT NOOOO SCAMS IF YOU ANSWER WITH A LINK YOU WILL GET REPORTED!!!!!!
    7·1 answer
  • 12.<br> Perimeter:<br> y-1<br> 2y + 3<br> 3y + 4
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!