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3 years ago

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How do you solve this

1 answer:

beks73 [17]3 years ago

4 0

Answer:

In all x keep the value of x 5 then the answer can get.

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Hamburger meat is $2.19 per pound. A box of spaghetti noodles is $0.79.

Karo-lina-s [1.5K]

Answer:

(2.19 x 4) + (0.79 x 3)

Step-by-step explanation:

ok so u hv to take 2.19 and multiply it by four. Then take 0.79 and multiply it by three.

8 0

3 years ago

Read 2 more answers

Find the vectors T, N, and B at the given point. r(t) = < t^2, 2/3t^3, t >, (1, 2/3 ,1)

maxonik [38]

Answer with Step-by-step explanation:

We are given that

$r(t)=< t^2,\frac{2}{3}t^3,t >$

We have to find T,N and B at the given point t > (1, $2/3$ ,1)

$r'(t)=$

$\mid r'(t) \mid=\sqrt{(2t)^2+(2t^2)^2+1}=\sqrt{(2t^2+1)^2}=2t^2+1$

$T(t)=\frac{r'(t)}{\mid r'(t)\mid}=\frac{}{2t^2+1}$

Now, substitute t=1

$T(1)=\frac{}{2+1}=\frac{1}{3}$

$T'(t)=\frac{-4t}{(2t^2+1)^2} +\frac{1}{2t^2+1}$

$T'(1)=-\frac{4}{9}+\frac{1}{3}$

$T'(1)=\frac{1}{9}=$

$\mid T'(1)\mid=\sqrt{(\frac{-2}{9})^2+(\frac{4}{9})^2+(\frac{-4}{9})^2}=\sqrt{\frac{36}{81}}=\frac{2}{3}$

$N(1)=\frac{T'(1)}{\mid T'(1)\mid}$

$N(1)=\frac{}{\frac{2}{3}}=$

$N(1)=$

$B(1)=T(1)\times N(1)$

$B(1)=\begin{vmatrix}i&j&k\\\frac{2}{3}&\frac{2}{3}&\frac{1}{3}\\\frac{-1}{3}&\frac{2}{3}&\frac{-2}{3}\end{vmatrix}$

$B(1)=i(\frac{-4}{9}-\frac{2}{9})-j(\frac{-4}{9}+\frac{1}{3})+k(\frac{4}{9}+\frac{2}{9})$

$B(1)=-\frac{2}{3}i+\frac{1}{3}j+\frac{2}{3}k$

$B(1)=\frac{1}{3}$

5 0

3 years ago

Dad gave Tyler and Emily the same amount of pocket money Emily bought a t shirt for $41 and she had $6 left how much money did d

Lady_Fox [76]

Answer:

Dad gave Tyler $47.

Step-by-step explanation:

You add the money that Emily had left and the cost of the t-shirt.

41+6= 17

6 0

3 years ago

Read 2 more answers

A robot moving forward at a constant speed takes 2.5 hours to travel 1 kilometer. Moving forward at this same constant speed, it

makvit [3.9K]

Answer:

The length of the hallway is 10 m.

Step-by-step explanation:

Given:

Time taken to cover 1 km = 2.5 hours

Distance covered in 2.5 hours = 1 km

Therefore, speed of robot = $\frac{\textrm{Distance}}{\textrm{TIme}}=\frac{1}{2.5}=0.4\ km/h$

Now, speed is constant.

Now, time taken to cover the length of hallway = 90 s

Speed of the robot = 0.4 km/h

Converting 0.4 km/h to m/s, we multiply by the factor $\frac{5}{18}$ . This gives,

$0.4\times \frac{5}{18}=\frac{1}{9}\ m/s$

Now, distance of the hallway is equal to the product of speed and time. So,

Distance of hallway = Speed $\times$ Time

Distance of hallway = $\frac{1}{9}\times 90=\frac{90}{9}=10\ m$

Therefore, the length of the hallway is 10 m.

5 0

3 years ago

HELP me look at pics

Setler [38]

M+n+3+m+n+4
=3m+2n+7

answer
C. 3m+2n+7

3 0

3 years ago

Read 2 more answers