Answer:
\frac{13+\left(-3\right)^2+4\left(-3\right)+1-\left(-10-\left(-6\right)\right)}{\frac{\left(4+5\right)}{\left(4^2-3^2\left(4-3\right)-8\right)}+12}=5
Step-by-step explanation:
Answer:
Step-by-step explanation:
Verifying pairs:
(1,0)
- 0 = 6*1 - 2
- 0 = 4 - incorrect
(5, 28)
- 28 = 6*5 - 2
- 28 = 30 -2
- 28 = 28 - correct
(6, 20)
- 20 = 6*6 - 2
- 20 = 36 - 2
- 20 = 34 - incorrect
(3, 19)
- 19 = 6*3 - 2
- 19 = 18 - 2
- 19 = 16 - incorrect
