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3 years ago

How can a Line Plot help you find an average with data given in Fractions?

Mathematics

2 answers:

umka2103 [35]3 years ago

7 0

Answer:

I did not understand its confusing

Hoochie [10]3 years ago

6 0

Answer: Since it tells you where everyone is and where the average is, it's helpful.

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Need help with this trigonometry word problem

kobusy [5.1K]

Answer:

86.6

Step-by-step explanation:

Here, AB represents height of the building, BC represents distance of the building from the point of observation.

In the right triangle ABC, the side which is opposite to the angle 60 degree is known as opposite side (AB), the side which is opposite to 90 degree is called hypotenuse side (AC) and the remaining side is called adjacent side (BC).

Now we need to find the length of the side AB.

tanθ = Opposite side/Adjacent side

tan 60° = AB/BC

√3 = AB/50

√3 x 50 = AB

AB = 50√3

Approximate value of √3 is 1.732

AB = 50 (1.732)

AB = 86.6 m

So, the height of the building is 86.6 m

4 0

3 years ago

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I need it right now please help me!

tankabanditka [31]

I can't directly tell you the answer, but I can help you for how to do it.

So every single time you want to find the rate of change (slope) label 2 points with x1, y1, x2 and y2. We can use the point-slope form to sind the slope:

y1-y2/x1-x2

And we just need to plug in the point to get the Y intercept.

When the x is 0, the y value will be the y-intercept.

The slope intercept form is: y=Mx+B. M stands for slope and B stand for y-intercept. Just plug the slope and y-intercept in and get the answer.

6 0

3 years ago

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30p questions hurry need your help pleaseeee!!

Ber [7]

Yes she can find the average colour by adding up all the amount of colors by how many colors there are.

6 0

3 years ago

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Suppose a certain manufacturing company produces connecting rods for 4- and 6-cylinder automobile engines using the same product

gregori [183]

Answer:

Generally the constraint that sets next week are shown below

Generally the constrain that sets next week maximum production of connecting rod for 4 cylinder to W_4 or 0 is

$x_4 \le W_4 * s_4$

$x_4 \le 5000 * s_4$

Generally the constrain that sets next week maximum production of connecting rod for 6 cylinder to W_6 or 0 is

$x_6 \le W_6 * s_6$

$x_6 \le 8,000 * s_6$

Generally the constrain that limits the production of connecting rods for both 4 cylinder and 6 cylinders is

$x_4 \le W_4 * s_6$

=> $x_4 \le 5000 * s_6$

$x_4 \le W_6 * s_4$

=> $x_4 \le 8000 * s_4$

$s_4 + s_6 = 1$

The minimum cost of production for next week is

$U = M_4 * x_4 + M_6 * x_6 + C_4 * s_4 + C_6 * s_6$

=> $U = 13x_4 + 16x_6 + 2000 s_4 + 3500 s_6$

Step-by-step explanation:

The cost for the four cylinder production line is $C_4 = \$2,100$

The cost for the six cylinder production line is $C_6 = \$3,500$

The manufacturing cost for each four cylinder is $M_4= \$13$

The manufacturing cost for each six cylinder is $M_6= \$16$

The weekly production capacity for 4 cylinder connecting rod is $W_4 = 5,000$

The weekly production capacity for 6 cylinder connecting rod is $W_6 = 8,000$

Generally the constraint that sets next week are shown below

Generally the constrain that sets next week maximum production of connecting rod for 4 cylinder to W_4 or 0 is

$x_4 \le W_4 * s_4$

$x_4 \le 5000 * s_4$

Generally the constrain that sets next week maximum production of connecting rod for 6 cylinder to W_6 or 0 is

$x_6 \le W_6 * s_6$

$x_6 \le 8,000 * s_6$

Generally the constrain that limits the production of connecting rods for both 4 cylinder and 6 cylinders is

$x_4 \le W_4 * s_6$

=> $x_4 \le 5000 * s_6$

$x_4 \le W_6 * s_4$

=> $x_4 \le 8000 * s_4$

$s_4 + s_6 = 1$

The minimum cost of production for next week is

$U = M_4 * x_4 + M_6 * x_6 + C_4 * s_4 + C_6 * s_6$

=> $U = 13x_4 + 16x_6 + 2000 s_4 + 3500 s_6$

3 0

4 years ago

NEED ASAP!! WILL MARK AS BRAINLIEST

Serga [27]

Use distance formula, line segment Uv is 5, vw is 6, and uw is square root of 61, add line segments up to get perimeter

5 0

2 years ago

Read 2 more answers