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2 years ago

13

In the equation 0.75s-5/8 = 44, how do you combine the like terms?

1 answer:

garri49 [273]2 years ago

6 0

Answer:

Step-by-step explanation:

In the given equation, the "like terms" are the constants 5/8 and 44.

It simplifies the math if we eliminate the fractions first. Note that 0.75 = 6/8, so now we have:

8(6/8)s - 8(5/8) = 44).

Multiplying all three terms by 8 (above) yields

8(6s) - 8(5) = 8(44), or

48s = 8(44 + 5), or 48s = 8(49)

Dividing both sides by 48 yields s: s = 8(49/48)

Review "like terms:" These are terms that have at least one characteristic in common. 5/8 and 44 are like terms because they are only constants (no variables are present). We must add 5/8 and 44. 0.75s does not have a "like term" in the given equation.

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X-(-6)=-2 EXPLAIN YOUR ANSWER

Zielflug [23.3K]

Answer:

If your asking for the Value of X the answer would be (-8)

Step-by-step explanation:

when your subtracting a negative, it's the same as addition, and if the equation should be equal to 2, then the answer would be (-8), because

(-8) - (-6) = -2.

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2 years ago

Using the slope formula, find the slope of the line (0,0) and (4,12)

riadik2000 [5.3K]

Answer:

The slope is 3

Step-by-step explanation:

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Hope this helps!

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2 years ago

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<img src="https://tex.z-dn.net/?f=5xy%20%7B%20-%20x%7D%20%5E%7B2%7D%20%7Bt%7D%20%20%2B%202xy%20%2B%203x%20%7B%7D%5E%7B2%7D%20t"

fenix001 [56]

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Step-by-step explanation:

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1 year ago

Point-Slope Form Practice

Lana71 [14]

Answer:

$y=-x-7$

Step-by-step explanation:

Equation of straight line in point slope form is given as

$y-y_1=m(x-x_1)$

Here

$m=-1 \ and \ (x_1, y_1)=(-2, -5)$

Therefore,

$y+5=-1(x+2)$

$y=-x-7$

4 0

2 years ago

find x if the distance between points L and M is 15 and point M is located in the first quadrant. L=(-6,2) M=(x,2)

aivan3 [116]

Answer:

Therefore,

$x = 9$

Step-by-step explanation:

Given:

Let,

point L( x₁ , y₁) ≡ ( -6 , 2)

point M( x₂ , y₂ )≡ (x , 2)

l(AB) = 15 units (distance between points L and M)

To Find:

x = ?

Solution:

Distance formula between Two points is given as

$l(LM)^{2} = (x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}$

Substituting the values we get

$15^{2}=(x--6)^{2}+(2-2)^{2}\\\\225=(x+6)^{2}$

Square Rooting we get

$(x+6)=\pm \sqrt{225}=\pm 15\\\\x+6 = 15\ or\ x+6 = -15\\\\x= 9\ or\ x = -21$

As point M is located in the first quadrant

x coordinate and y coordinate are positive

So x = -21 DISCARDED

Hence,

$x = 9$

Therefore,

$x = 9$

3 0

3 years ago