Answer:
The solved expression is
and ![x=3-\sqrt{2}](https://tex.z-dn.net/?f=x%3D3-%5Csqrt%7B2%7D)
Therefore ![x=3\pm\sqrt{2}](https://tex.z-dn.net/?f=x%3D3%5Cpm%5Csqrt%7B2%7D)
Step-by-step explanation:
Given quadratic equation is ![x^2-6x+7=0](https://tex.z-dn.net/?f=x%5E2-6x%2B7%3D0)
To solve the given equation by using completing the square :
![x^2-6x+7=0](https://tex.z-dn.net/?f=x%5E2-6x%2B7%3D0)
Rewritting the above equation as below :
![x^2-6x+7+2-2=0](https://tex.z-dn.net/?f=x%5E2-6x%2B7%2B2-2%3D0)
![(x^2-6x+7+2)-2=0](https://tex.z-dn.net/?f=%28x%5E2-6x%2B7%2B2%29-2%3D0)
![(x^2-6x+9)-2=0](https://tex.z-dn.net/?f=%28x%5E2-6x%2B9%29-2%3D0)
![(x^2-6x+3^2)-2=0](https://tex.z-dn.net/?f=%28x%5E2-6x%2B3%5E2%29-2%3D0)
( it is of the form of
heere a=x and b=3 )
![(x-3)^2-2=0](https://tex.z-dn.net/?f=%28x-3%29%5E2-2%3D0)
![(x-3)^2=2](https://tex.z-dn.net/?f=%28x-3%29%5E2%3D2)
Taking square root on both sides we get
![\sqrt{(x-3)^2}=\pm\sqrt{2}](https://tex.z-dn.net/?f=%5Csqrt%7B%28x-3%29%5E2%7D%3D%5Cpm%5Csqrt%7B2%7D)
![x-3=\pm\sqrt{2}](https://tex.z-dn.net/?f=x-3%3D%5Cpm%5Csqrt%7B2%7D)
![x=\pm\sqrt{2}+3](https://tex.z-dn.net/?f=x%3D%5Cpm%5Csqrt%7B2%7D%2B3)
![x=3\pm\sqrt{2}](https://tex.z-dn.net/?f=x%3D3%5Cpm%5Csqrt%7B2%7D)
Therefore
and ![x=3-\sqrt{2}](https://tex.z-dn.net/?f=x%3D3-%5Csqrt%7B2%7D)
You’ll need 1197 inches of paper
192 yards here is the answer
Answer:
40%
Step-by-step explanation:
i used a calculator
You cant even see the problems but get photomath it will help u out