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Gala2k [10]
3 years ago
5

the average age of a class of 20 students is 15 years and the average age of another class of 30 students is 20 years .find the

average age of students into classes​
Mathematics
2 answers:
Olegator [25]3 years ago
6 0

Let’s say the first class is X.

Avg(X)= x/20=15

X=300

Let’s say the second class is Y.

Avg(Y)= Y/30=20

Y=600

X+Y=900

AVG(X+Y)=900/(20+30)=900/50=18

The average of both classes is 18.

prisoha [69]3 years ago
4 0

Step-by-step explanation:

AVERAGE AGE OF 20 STUDENTS=15

AVERAGE AGE OF 30 STUDENTS=20

THEREFORE SUM OF Ages of 20 students=300

And sum of Ages of 30 students=600

Therefore Average age of 50 students =900/50=18

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Solve for y:<br> x + 2y = -8<br><br> y=-1/2x+4<br> y=-1/2x-4<br> y=-2x - 4<br> y=1/2x-4
adelina 88 [10]

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Need help Asap thank you in advance
julia-pushkina [17]

Answer:

12x^4-20x^2+32x=4x(3x^3-5x+8)

Step-by-step explanation:

<u>Common Factors</u>

An algebraic expression that is formed by sums or subtractions of terms can be factored provided there are numeric or variable common factors in all the terms.

The following expression

Z=12x^4-20x^2+32x

Can be factored in the constants and in the variable x.

1. To find the common factor of the variable, we must locate if the variable is present in all terms. If so, we take the common factor as the variable with an exponent which is the lowest of all the exponents found throughout the different terms. In this case, the lowest exponent is x (exponent 1).

2. To find the common factors of the constants, we take all the coefficients:

12 - 20 - 32

and find the greatest common divisor of them, i.e. the greatest number all the given numbers can be divided by. This number is 4, since 12/4=3, 20/4=5 and 32/4=8

3. The factored expression is

Z=12x^4-20x^2+32x=4x(3x^3-5x+8)

\boxed{12x^4-20x^2+32x=4x(3x^3-5x+8)}

3 0
3 years ago
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