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Gala2k [10]
3 years ago
5

the average age of a class of 20 students is 15 years and the average age of another class of 30 students is 20 years .find the

average age of students into classes​
Mathematics
2 answers:
Olegator [25]3 years ago
6 0

Let’s say the first class is X.

Avg(X)= x/20=15

X=300

Let’s say the second class is Y.

Avg(Y)= Y/30=20

Y=600

X+Y=900

AVG(X+Y)=900/(20+30)=900/50=18

The average of both classes is 18.

prisoha [69]3 years ago
4 0

Step-by-step explanation:

AVERAGE AGE OF 20 STUDENTS=15

AVERAGE AGE OF 30 STUDENTS=20

THEREFORE SUM OF Ages of 20 students=300

And sum of Ages of 30 students=600

Therefore Average age of 50 students =900/50=18

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The following data represent the number of people aged 25 to 64 years covered by health insurance​ (private or​ government) in 2
Yuri [45]

The mean age is equal to: 44.09.

The standard deviation is equal to: 10.07.

<h3>How to determine the mean age and standard deviation?</h3>

First of all, we would determine the median of each class interval as follows:

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Standard deviation, S = √((24.3 × (29.5 - 44.09)² + (36.1 × (39.5 - 44.09)² + (36.7 × (49.5 - 44.09)² + (20.9 × (59.5 - 44.09)²)/(24.3 + 36.1 + 36.7 + 20.9))

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