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enot [183]
3 years ago
8

Five students received the same text message at 9:00 AM Each of them sent the message to 5 more students at 10:00 AM. Each of th

ose students sent the message to 5 more students at 11:00 AM
Mathematics
1 answer:
hammer [34]3 years ago
8 0

Answer:

Step-by-step explanation:

25

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I need help on this pls
tresset_1 [31]

Answer:

Hello!

1 on the left in vertical and 1 on the right is adjacent hope that helps.

5 0
2 years ago
PLZ HELp
IceJOKER [234]

Answer:

The answer is 11 because 44 =4*11

Step-by-step explanation:

Please Brainlist me

7 0
2 years ago
Read 2 more answers
Joe earned money for baby-sitting , he spent 1/4 of the money on a guitar then he gave 1/4 to charity , if he has $108 left how
Mekhanik [1.2K]

Answer:

216 US dollars

Step-by-step explanation:

Let the amount he earned for babysitting be x

He spent 1/4 of x on guitar=(1/4)×x=1/4x

He gave 1/4 of x to charity= (1/4)×x=1/4x

Equation 1

Total amount left=(Total amount earned -Total amount spent)

Total amount earned=x

Total amount spent=(Spent on Guitar+Spent on Charity)=(1/4x)+(1/4x)=1/2x=0.5x

Total amount left=108 US dollars

Substituting in equation 1

108=(x-0,5x)

Solving

0.5x/0.5=108/0.5

x=216 US dollars

He started with 216 US dollars

3 0
3 years ago
The sum of three consecutive odd integers is 87. Which equation could you use to find the three
Alexandra [31]

Answer:

k+(k+2)+(k+4)=87

The largest integer is 31.

Step-by-step explanation:

Hi there!

Let <em>k</em> be equal to the smallest of the integers.

Let (<em>k</em>+2) be the next odd integer.

Let (<em>k</em>+4) be the final odd integer.

We're given that the sum of these three integers is 87. Construct an equation:

k+(k+2)+(k+4)=87

Combine like terms:

k+k+2+k+4=87\\3k+6=87\\3k=81\\k=27

Therefore, the smallest integer is 27. Because the largest integer is k+4, the largest integer is therefore 31.

I hope this helps!

7 0
3 years ago
In order to estimate the difference between the average hourly wages of employees of two branches of a department store, the fol
Vinil7 [7]

Answer:

4.692 to 7.308

Step-by-step explanation:

Given :

n1 = 25 ; n2 = 20 ;

Mean x1 = $12 ; mean x2 = $6

Standard deviation, s1 = 3 ; s2 = 1

Confidence interval :

(x1 - x2) ± t*√(s1²/n1) + (s2²/n2)

x1 - x2 = (12 - 6) = 6

√(s1²/n1) + (s2²/n2) = √(3²/25) + (1²/20) = 0.640

Degree of freedom :

((s1²/n1) + (s2²/n2))² / (s1²/n1)²/n1-1 + (s2²/n2)²/n2-1

Numerator = 0.1681

Denominator = 0.0054 + 0.0001315 = 0.0055315

Degree of freedom = 0.1681 / 0.0055315 = 30.38 = 30

Tcritical at 0.05, df = 30 = 2.042272

Hence ;

6 ± 2.042272(0.640)

6 ± 1.30705408

Lower boundary = 6 - 1.30705408 = 4.69294592

Upper boundary = 6 + 1.30705408 = 7.30705408

(4.693 ; 7.307)

3 0
2 years ago
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