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2 years ago

It costs 12 dollars for 8 hot dogs. )

Mathematics

1 answer:

Advocard [28]2 years ago

7 0

Answer:

$1.50

Step-by-step explanation:

$12, the amount of money divided by 8, the number of hot dogs, equals $1.50, the amount for 1 hot dog.

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Tom has 3 kids, the product of their ages is 72. What is the sum of their ages?

mafiozo [28]

Their ages are 24 years old each.

5 0

3 years ago

Read 2 more answers

Given: y" - 2y' = 6t + 5e^2t. Find the correct form to use for y_p if the equation is solved using Undetermined coefficients. Do

const2013 [10]

Answer:

$y_p=A+Bt+Ce^{2t}$

Step-by-step explanation:

Given: $y'' - 2y' = 6t + 5e^{2t}$ .

we need to find the correct form for $y_p$ if the equation is solve using undetermined coefficients.

A first order differential equation $\frac{\mathrm{d} y}{\mathrm{d} x}=f\left ( x,y \right )$ is said to be homogeneous if $f(tx,ty)=f(x,y)$ for all t.

Consider homogeneous equation $y''-2y'=0$

Let $y=e^{rt}$ be the solution .

We get $(r^2-2r)e^{rt}=0$

Since $e^{rt}\neq 0$ , $r^2-2r=0$ .

So, we get solution as $y_c=c_1+c_2e^{2t}$

As constant term and $e^{2t}$ are already in the R.H.S of equation

$y" - 2y' = 6t + 5e^{2t}$ , we can take $y_p$ as $y_p=A+Bt+Ce^{2t}$

6 0

3 years ago

How do you do this question it is kinda difficult to understand

Dafna1 [17]

Speed = slope of the line = 20 / 0.5 = 40 km / hr

Second part will be a line with downward slope from the end of the horizontal line Slop = 20 / 1/3 (=60 km/h) So it will pass through the 65 on horizontal axis.

4 0

2 years ago

How many meters tall is a door

S_A_V [24]

Answer: a standard door is about 2-2.10 meters

Step-by-step explanation:

8 0

2 years ago

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A line includes the points (10,-5) and (-10,-1). What is the equation in slope intercept form?

Elodia [21]

$\bf (\stackrel{x_1}{10}~,~\stackrel{y_1}{-5})\qquad (\stackrel{x_2}{-10}~,~\stackrel{y_2}{-1}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{-1-(-5)}{-10-10}\implies \cfrac{-1+5}{-20}\implies \cfrac{4}{-20}\implies -\cfrac{1}{5} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-(-5)=-\cfrac{1}{5}(x-10) \\\\\\ y+5=-\cfrac{1}{5}x+2\implies y=-\cfrac{1}{5}x-3$

8 0

2 years ago