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Lapatulllka [165]
3 years ago
13

Jada ran 15.25 kilometers. Han ran 8,500 meters. Who ran farther?

Mathematics
1 answer:
Thepotemich [5.8K]3 years ago
4 0

Answer:

Jada

Step-by-step explanation:

We are given Jada's distance in kilometers and Han's distance in meters. To compare the two we need to have them both in the same unit of measurement.

One kilometer is equal to 1000 meters, so Jada ran 15.25*1000=15250 meters.

Compared to Han, who ran 8500 meters, Jada ran farther. 15250>8500.

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bixtya [17]

Answer:

B

Step-by-step explanation:

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8 0
3 years ago
Which box shows a relationship where the constant of proportionality is 64?
Sever21 [200]

Answer:

C

Step-by-step explanation:

Constant of proportionality = \frac{y}{x}

Let's find out which if the boxes will give us 64 as constant of proportionality.

A. \frac{y}{x} = \frac{11}{2} = 5.5 ≠ 64

B. \frac{y}{x} = \frac{5}{15} = \frac{1}{3} ≠ 64

C. \frac{y}{x} = \frac{16}{\frac{1}{4}} = 16*\frac{4}{1} = 64 ≠ 64

D. \frac{y}{x} = \frac{\frac{3}{7}}{3} = \frac{3}{7}*\frac{1}{3} = \frac{1}{7} ≠ 64

E. \frac{y}{x} = \frac{2}{-10} = -\frac{1}{5} ≠ 64

F. \frac{y}{x} = \frac{21}{6} = \frac{7}{2} ≠ 64

G. \frac{y}{x} = \frac{4}{8} = \frac{1}{2} ≠ 64

From the boxes given, box C is the only box that shows us a relationship where the constant of proportionality is 64.

7 0
3 years ago
Y=-2x-3,y=-2x+2 how many solutions does the system have
denis23 [38]

Answer:

3x + 3 = -2x + 3

3x + 2x = 3 - 3

5x = 0

x =0.

So y = 3(0) + 3 = 3.

Step-by-step explanation:

7 0
3 years ago
PLEASE ANSWER IN THE SCREENSHOT. I WILL MARK BRAINLYEST
Nimfa-mama [501]
Yes, the table is correct
There would be 60 squares as the ratio of triangles to squares is 3:4
6 0
3 years ago
Is X +3 a factor of 2X squared minus 2X -12
Fantom [35]

Answer: No, x+3 is not a factor of 2x^2-2x-12

========================================================

Explanation:

Let p(x) = 2x^2 - 2x - 12

If we divide p(x) over (x-k), then the remainder is p(k). I'm using the remainder theorem. A special case of the remainder theorem is that if p(k) = 0, then x-k is a factor of p(x).

Compare x+3 = x-(-3) to x-k to find that k = -3.

Plug x = -3 into the function

p(x) = 2x^2 - 2x - 12

p(-3) = 2(-3)^2 - 2(-3) - 12

p(-3) = 12

We don't get 0 as a result so x+3 is not a factor of p(x) = 2x^2 - 2x - 12

----------------------------------------

Let's see what happens when we factor p(x)

2x^2 - 2x - 12

2(x^2 - x - 6)

2(x - 3)(x + 2)

The factors here are 2, x-3 and x+2

3 0
3 years ago
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