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serg [7]
2 years ago
9

The admission fee at the fair is $1.50 for children and $4 for adults. On a certain day, a total pf 2200 people entered the fair

and $5050 in entrance fees were collected.
Let c represent the number of children and let a represent the number of adults.

Choose the two equations that will create our system of equations for the story problem.


c+a=2200

1.50c+4a=5050

1.50a+4c=5050

c+a=5050
Mathematics
2 answers:
Afina-wow [57]2 years ago
7 0

Answer:

c+a=2200

Step-by-step explanation:

I did the test on K12, so if you also have the same test I promise you its correct.

Butoxors [25]2 years ago
6 0

Answer: the picture

Step-by-step explanation:

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John earns $6000. He spends $1000 on rent, $1500 on grocery, $500 on travel and saves the rest. What size angle should be drawn
Arada [10]

Answer:

$3000

Step-by-step explanation:

6000-1000-1500-500= $3000

7 0
2 years ago
Picture attached what steps are needed plz help
aksik [14]
B.) 2p-3.50 he bought 2 shirts so 2p and than a coupon for 3.50 so subtract it from 2p and ur answer is 2p-3.50
5 0
3 years ago
What direction for negative and positive go in​
skad [1K]

Answer:

negative=left positive=right

Step-by-step explanation:

negatives are less than positives

8 0
3 years ago
Read 2 more answers
Re-write the quadratic function below in Standard Form<br> y=-3 (x - 2)² – 7
pav-90 [236]

Answer:

y=-3x^2+12x-19

Step-by-step explanation:

we know that

The quadratic equation in standard form is equal to

y=ax^{2} +bx+c

we have

y=-3(x-2)^{2}-7

This is a quadratic equation in vertex form

Convert to standard form

y=-3(x^2-4x+4)-7

Apply distributive property

y=-3x^2+12x-12-7

Combine like terms

y=-3x^2+12x-19 ----> quadratic equation in standard form

3 0
2 years ago
12What mistake did the student make when solvingtheir two-step equation?(a)b) If correctly solved what should the value of be?
mixas84 [53]

Given the equation:

\frac{x}{6}+3=-18

(a) You can identify that the student applied the Subtraction Property of Equality by subtraction 3 from both sides of the equation:

\frac{x}{6}+3-(3)=-18-(3)

However, the student made a mistake when adding the numbers on the right side.

Since you have two numbers with the same sign on the right side of the equation, you must add them, not subtract them and use the same sign in the result. Then, the steps to add them are:

- Add their Absolute values (their values without the negative sign).

- Write the sum with the negative sign.

Then:

\frac{x}{6}=-21

(b) The correct procedure is:

1. Apply the Subtraction Property of Equality by subtracting 3 from both sides (as you did in the previous part):

\begin{gathered} \frac{x}{6}+3-(3)=-18-(3) \\  \\ \frac{x}{6}=-21 \end{gathered}

2. Apply the Multiplication Property of Equality by multiplying both sides of the equation by 6:

\begin{gathered} (6)(\frac{x}{6})=(-21)(6) \\  \\ x=-126 \end{gathered}

Hence, the answers are:

(a) The student made a mistake by adding the numbers -18 and -3:

-18-3=-15\text{ (False)}

(b) The value of "x" should be:

x=-126

4 0
1 year ago
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