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slamgirl [31]
3 years ago
6

How much energy is required to vaporize 185 g of butane at its boiling point? The heat of vaporization for butane is 23.1 kJ/mol

. Express your answer to three significant figures and include the appropriate units.
Mathematics
1 answer:
arlik [135]3 years ago
6 0

Answer:

73.5 kJ

Step-by-step explanation:

Mass of butane = 185 g

Heat of vaporization for butane = 23.1 kJ/mol

Molar mass of butane = 58.12 g/mol

Number of moles of butane = \frac{\text{Mass of butane}}{\text{Molar mass of butane}}=\frac{185}{58.12}=3.18\ moles

Energy required for burning 185 g of butane = 3.18×23.1 = 73.5 kJ

∴ Energy is required to vaporize 185 g of butane at its boiling point is 73.5 kJ

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Answer:

f =38

Step-by-step explanation:

f-3/4=5/6

f-3×6=5×4

f-18 =20

f =20+18

f =38

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2 years ago
Write 0.15151515 as a fraction
leonid [27]

Answer:

5/33

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3 years ago
Nike reported a profit of $28,951,000 for one quarter (3 months), a profit of $20,570,000 for the second quarter, a profit of $1
Olenka [21]

Answer:

\$16,826,000.

Step-by-step explanation:

We have been given that Nike reported a profit of $28,951,000 for one quarter (3 months), a profit of $20,570,000 for the second quarter, a profit of $15,342,000 the third quarter, and a loss of $48,037,000 for the fourth quarter.

To find the net profit for year, we will subtract the loss in the 4th quarter from the sum of profit in 3 quarters as:

\text{Net profit for the year}=\$28,951,000+\$20,570,000+\$15,342,000-\$48,037,000

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\text{Net profit for the year}=\$16,826,000

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4 0
3 years ago
A set of data items is normally distributed with a mean of 240 and a standard deviation of 32. Convert 272 to a? z-score
dem82 [27]

Answer:

z-score = 1

Step-by-step explanation:

Given

Mean= μ=240

SD= σ=32

In order to find the z-score of a value, the mean is subtracted from the value and then divided by standard deviation.

The formula for z-score is:

z-score=(x-μ)/σ

Here x is the value whose z-score is to be found.

In the given question, x = 272

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Hope this helps! Message me with any questions!

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