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ra1l [238]
3 years ago
10

Rob deposits $1,000 in a savings account that pays 4.4% interest compounded monthly. A) How much is in his account at the end of

one year? B) What is his Annual Percentage Yield for his account as percent?​
Mathematics
1 answer:
kirill115 [55]3 years ago
7 0
1528 in one year and 5% yield
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A recipe calls for 2 cups of water for every 3 cups of flour. How much water is needed if you use 12 cups of flour?
Tju [1.3M]

Answer:

8 cups of water

Explanation:

2 cups of water = 3 cups of flour

x cups of water = 12 cups of flour

12/3=4

2x4=8

6 0
3 years ago
How many matches are needed to form figure number 9 and 17? explain​
saveliy_v [14]

Answer:

Please find the complete question in the attached file.

Step-by-step explanation:

For point 1:

At this point we make up triangles for the first one makes up by 3 matches figure 2 make up by 5 matches figure 3 makes up by 7 matches.

For point 2:

 4 \ \ 5\ \   6\ \   7\ \   8  you can try to  

9 \ \  11\ \ 13 \ \ 15 \ \ 17 draw to find  values  

For point 3:

number of matches= 1+2 \times \ figure\  number\\\\

For point 4:

1+2 \times 9=19 \ \ (use \ law \ of\  (iii)) \\\\1+2 \times 17=35

3 0
3 years ago
It costs $50 to join a bowling club plus a monthly fee, the total costs for the year is $350
kvasek [131]
$25 a month :)  (its too short so i hope you have a lovely day)
5 0
3 years ago
Wanna help a girl out
Bad White [126]

Answer: 3580.50

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Hello I need help Finding the probability
Stolb23 [73]
Each petal of the region R is the intersection of two circles, both of diameter 10. Each petal in turn is twice the area of a circular segment bounded by a chord of length 5\sqrt2, which implies the segment is subtended by an angle of \dfrac\pi2. This means the area of the segment is

\text{area}_{\text{segment}}=\text{area}_{\text{sector}}-\text{area}_{\text{triangle}}
\text{area}_{\text{segment}}=\dfrac{25\pi}4-\dfrac{25}2

This means the area of one petal is \dfrac{25\pi}2-25, and the area of R is four times this, or 50\pi-100.

Meanwhile, the area of G is simply the area of the square minus the area of R, or 10^2-(50\pi-100)=200-50\pi.

So

\mathbb P(X=R)=\dfrac{50\pi-100}{100}=\dfrac\pi2-1
\mathbb P(X=G)=\dfrac{200-50\pi}{100}=2-\dfrac\pi2
\mathbb P((X=R)\land(X=G))=0 (provided these regions are indeed disjoint; it's hard to tell from the picture)
\mathbb P((X=R)\lor(X=G))=\mathbb P(X=R)+\mathbb P(X=G)=1

4 0
3 years ago
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