AD = AB
AD = 2r+8
AB = 5r-13
we need to find the value of r to find the total length
so 2r+8 = 5r-13
subtract 2r from each side:
8 = 3r -13
add 13 to each side:
21 = 3r
divide both sides by 3
r = 21 / 3 = 7
r=7
now we know r, so replace r with 7 in the equation for AD
AD = 2r+8 = 2(7) +8 = 14 +8 = 22
the answer is D. 22
Answer:
7-16x=10. I'm sorry I'm not good at math but it never hurts try, right?
Step-by-step explanation:
Multiply the parentheses first which would give you
8-6x+10x-15.
Next add 6x+10x which would give you
8-16x-15.
Then subtract 8-15 which would give you
7-16x=20-5x2. Then work the problem from there.
7-16x=20-10.
7-16x=10.
Answer:
972 x^16 y^24
Step-by-step explanation:
Simplify the following:
(-2 x^3 y^7)^2 (3 x^2 y^2)^5
Multiply each exponent in -2 x^3 y^7 by 2:
(-2)^2 x^(2×3) y^(2×7) (3 x^2 y^2)^5
2×7 = 14:
(-2)^2 x^(2×3) y^14 (3 x^2 y^2)^5
2×3 = 6:
(-2)^2 x^6 y^14 (3 x^2 y^2)^5
(-2)^2 = 4:
4 x^6 y^14 (3 x^2 y^2)^5
Multiply each exponent in 3 x^2 y^2 by 5:
4 x^6 y^14×3^5 x^(5×2) y^(5×2)
5×2 = 10:
4×3^5 x^6 y^14 x^(5×2) y^10
5×2 = 10:
4×3^5 x^6 y^14 x^10 y^10
3^5 = 3×3^4 = 3 (3^2)^2:
4×3 (3^2)^2 x^6 y^14 x^10 y^10
3^2 = 9:
4×3×9^2 x^6 y^14 x^10 y^10
9^2 = 81:
4×3×81 x^6 y^14 x^10 y^10
3×81 = 243:
4×243 x^6 y^14 x^10 y^10
4 x^6 y^14×243 x^10 y^10 = 4 x^(6 + 10) y^(14 + 10)×243:
4×243 x^(6 + 10) y^(14 + 10)
14 + 10 = 24:
4×243 x^(6 + 10) y^24
6 + 10 = 16:
4×243 x^16 y^24
4×243 = 972:
Answer: 972 x^16 y^24
Order of Operations, I'm pretty sure
