Using the law of sines, we have
And we know that
So, the equation becomes
Tell me the problems and i may be able to help
HIAB
1)H, 2)I, 3)A, 4)B.
When there is only points and no lines, to find domain, you give the x values only, and to find the range you give the y values only.
When there is a line, for domain you go from left to right, and for range you go from bottom to top. The arrow indicates that the line is continuous, and so the second values for domain and range are infinity because we do not know the value.
Answer:
Step-by-step explanation:
Expand it: 
Add 10 to both sides: 
Divide both sides by 3: 
Find <em>a</em>, <em>b</em> for 
It’s 
So, inserting it leads to: 
Subtract <em>b</em> from both sides: 
Apply square root to both sides and consider the two solutions: 
Subtract 3 from both sides and you get 
Hello :
<span>an equation of the circle Center at the
w(a,b) and ridus : r is :
(x-a)² +(y-b)² = r²
In this exercice : (x-3)²+y²=7² ....a =3 and b=0 ( the center is :w(3,0)) ... r=7
The distance between each point in each case is calculated and compared with the length of the radius
1 ) </span>A (-1, 1) : Aw² = (-1-3)²+1² =17..... Aw < r : <span>interior the circle
</span> 2 ) B(10, 0) :Bw² =(10-3)²+0² =49 ......r = Bw :<span>circumference of the circle
</span> 3 ) C(4, -8) :Cw² = (4-3)²+(-8)² =65..... Cw > r : exterior the circle
