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2 years ago

Please helppp ;-; how do you determine the end behavior of a function?

Mathematics

1 answer:

Karolina [17]2 years ago

3 0

Answer:

End Behavior of a Function. The end behavior of a polynomial function is the behavior of the graph of f( x ) as x approaches positive infinity or negative infinity. The degree and the leading coefficient of a polynomial function determine the end behavior of the graph.

Step-by-step explanation:

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The author drilled a hole in a die and filled it with a lead weight, then proceeded to roll it 200 times. Here are the observed

algol [13]

Answer:

$\chi^2 = \frac{(27-33.33)^2}{33.33}+\frac{(31-33.33)^2}{33.33}+\frac{(42-33.33)^2}{33.33}+\frac{(40-33.33)^2}{33.33}+\frac{(28-33.33)^2}{33.33}+\frac{(32-33.33)^2}{33.33} =5.860$

$p_v = P(\chi^2_{5} >5.860)=0.32$

Since the p value is higher than the significance level assumed 0.05 we FAIL to reject the null hypothesis at 5% of significance, and we can conclude that we can assume that we have equally like results.

Step-by-step explanation:

A chi-square goodness of fit test "determines if a sample data matches a population".

A chi-square test for independence "compares two variables in a contingency table to see if they are related. In a more general sense, it tests to see whether distributions of categorical variables differ from each another".

Assume the following dataset:

Number: 1, 2 , 3 , 4 , 5 ,6

Frequency: 27, 31, 42, 40, 28, 32

We need to conduct a chi square test in order to check the following hypothesis:

H0: The outcomes are equally likely.

H1: The outcomes are not equally likely.

The level of significance assumed for this case is $\alpha=0.05$

The statistic to check the hypothesis is given by:

$\chi^2 =\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}$

The observed values are given:

$O_{1}=27$ $O_{2}=31$

$O_{3}=42$ $O_{4}=40$

$O_{5}=28$ $O_{6}=32$

The expected values are given by:

$E_{1} =\frac{1}{6}*200=33.33$ $E_{2} =\frac{1}{6}*200=33.33$

$E_{3} =\frac{1}{6}*200=33.33$ $E_{4} =\frac{1}{6}*200=33.33$

$E_{5} =\frac{1}{6}*200=33.33$ $E_{6} =\frac{1}{6}*200=33.33$

And now we can calculate the statistic:

$\chi^2 = \frac{(27-33.33)^2}{33.33}+\frac{(31-33.33)^2}{33.33}+\frac{(42-33.33)^2}{33.33}+\frac{(40-33.33)^2}{33.33}+\frac{(28-33.33)^2}{33.33}+\frac{(32-33.33)^2}{33.33} =5.860$

Now we can calculate the degrees of freedom for the statistic given by:

$df=Categories-1=6-1=5$

And we can calculate the p value given by:

$p_v = P(\chi^2_{5} >5.860)=0.32$

And we can find the p value using the following excel code:

"=1-CHISQ.DIST(5.860,5,TRUE)"

4 0

3 years ago

Help me with these please!

Law Incorporation [45]

Answer:

wut is it

Step-by-step explanation:

5 0

3 years ago

Use proportions to solve the following problem. A recipe calls for 4 eggs and 3 cups of milk. To prepare for a larger number of

dybincka [34]

Answer:

16.5 cups of milk are needed.

Step-by-step explanation:

i hate you for reporting my answer.

3 0

2 years ago

AABC is reflected across the x-axis. What is the new location of point B? A (-4, -2) C (4, -2) B (-4,2) D (4,2)

Molodets [167]

Answer:

D (4,2)

Step-by-step explanation:

you just change the y value to the opposite sign hehe

7 0

2 years ago

When you multiply any whole number by the one before it, the result is always an even number.

polet [3.4K]

Verrrrrrry interesting ! / / / Every multiple of an even number is another even number. When you take any whole number and the one 'before' it ... no matter which direction 'before' means .... one of the numbers is even. So their product is a multiple of an even number, and it must be another even number.

8 0

2 years ago