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Bad White [126]
3 years ago
9

If C = 18π inches, what is the area?

Mathematics
2 answers:
raketka [301]3 years ago
8 0

Answer:254.34

Step-by-step explanation:if you get it rong im sorry

Contact [7]3 years ago
3 0

Answer:

254.34 in^2

Step-by-step explanation:

C = 18(3.14)

C = 56.52

A = C^2/4(3.14)

A = (56.52)^2 = 3194.5104

A = 3194.5104/4(3.14) = 254.34

Hope this makes sense

You might be interested in
find the angle between the vectors. (first find the exact expression and then approximate to the nearest degree. ) a=[1,2,-2]. B
SashulF [63]

Answer:

\theta = cos^{-1} (\frac{10}{\sqrt{9} \sqrt{25}})=cos^{-1} (\frac{10}{15}) = cos^{-1} (\frac{2}{3}) = 48.190

Since the angle between the two vectors is not 180 or 0 degrees we can conclude that are not parallel

And the anfle is approximately \theta \approx 48

Step-by-step explanation:

For this case first we need to calculate the dot product of the vectors, and after this if the dot product is not equal to 0 we can calculate the angle between the two vectors in order to see if there are parallel or not.

a=[1,2,-2], b=[4,0,-3,]

The dot product on this case is:

a b= (1)*(4) + (2)*(0)+ (-2)*(-3)=10

Since the dot product is not equal to zero then the two vectors are not orthogonal.

Now we can calculate the magnitude of each vector like this:

|a|= \sqrt{(1)^2 +(2)^2 +(-2)^2}=\sqrt{9} =3

|b| =\sqrt{(4)^2 +(0)^2 +(-3)^2}=\sqrt{25}= 5

And finally we can calculate the angle between the vectors like this:

cos \theta = \frac{ab}{|a| |b|}

And the angle is given by:

\theta = cos^{-1} (\frac{ab}{|a| |b|})

If we replace we got:

\theta = cos^{-1} (\frac{10}{\sqrt{9} \sqrt{25}})=cos^{-1} (\frac{10}{15}) = cos^{-1} (\frac{2}{3}) = 48.190

Since the angle between the two vectors is not 180 or 0 degrees we can conclude that are not parallel

And the anfle is approximately \theta \approx 48

3 0
2 years ago
Please help me with this question thank you
Fantom [35]
If the answer is an equation then it is:
x=(4y+15)/(5-3y)
8 0
3 years ago
Read 2 more answers
Is RS perpendicular to DF? Select Yes or No for each statement. R (6, −2), S (−1, 8), D (−1, 11), and F (11 ,4) R (1, 3), S (4,7
guajiro [1.7K]

I'll do the first one to get you started.  

Find the slope of the line between R (6,-2) and S (-1,8) to get

m = (y2-y1)/(x2-x1)

m = (8-(-2))/(-1-6)

m = (8+2)/(-1-6)

m = 10/(-7)

m = -10/7

The slope of line RS is -10/7

Next, we find the slope of line DF

m = (y2 - y1)/(x2 - x1)

m = (4-11)/(11-(-1))

m = (4-11)/(11+1)

m = -7/12

From here, we multiply the two slope values

(slope of RS)*(slope of DF) = (-10/7)*(-7/12)

(slope of RS)*(slope of DF) = (-10*(-7))/(7*12)

(slope of RS)*(slope of DF) = 10/12

(slope of RS)*(slope of DF) = 5/6

Because the result is not -1, this means we do not have perpendicular lines here. Any pair of perpendicular lines always has their slopes multiply to -1. This is assuming neither line is vertical.

I'll let you do the two other ones. Let me know what you get so I can check your work.

3 0
2 years ago
Need help fast! with both questions
Eduardwww [97]

Answer:

first one is 41 i think and the second is 30 for sure

Step-by-step explanation:

6 0
2 years ago
48=3 times 2 to the power of a 56=7 times 2 to the power of bWhat are the values of a and b?a= b=
Digiron [165]

9514 1404 393

Answer:

  • a = 4
  • b = 3

Step-by-step explanation:

From your knowledge of multiplication tables, you know ...

  48 = 6·8 = 3·2·2·2·2 = 3·2^4 . . . . a = 4

  56 = 7·8 = 7·2·2·2 = 7·2^3 . . . . . . b = 3

8 0
2 years ago
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