1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Diano4ka-milaya [45]
3 years ago
13

I need help I will give 100 points and brainliest

Mathematics
2 answers:
pochemuha3 years ago
5 0

Answer:

ytryutrujyjutt

Step-by-step explanation:

Anit [1.1K]3 years ago
4 0

Answer:

5. 9/2 6. 9/4 7. 7/2 8. 8/3 9. 2/3

Step-by-step explanation:

Hope I helped!!

You might be interested in
Pls help! (put a joke in ur awnser)
djverab [1.8K]

Answer:

r⁶

Step-by-step explanation:

Cancel the common factors or r⁹ and r³

3 0
3 years ago
Read 2 more answers
Use x=5, equals, 5 to identify the value of each expression.
Lesechka [4]

Answer:

The answer to the first question is 625

The answer to the second question is 1

The answer to the third question is 1

4 0
3 years ago
Read 2 more answers
The accompanying data on IQ for first-graders at auniversity lab school was introduced in Example 1.2.82 96 99 102 103 103 106 1
almond37 [142]

Answer:

Mean = 113.72

The estimator of 113.72 is point estimate used for the  conceptual population of all first-graders in this school

Step-by-step explanation:

Data provided in the question:

Data:

82 96 99 102 103 103 106 107 108 108 108 108 109 110 110 111 113 113 113 113 115 115 118 118 119 121 122 122 127 132 136 140 146

Number of data = 33

In the hint it is also given that the sum of the data value i.e ∑x = 3753

Now,

Point estimate of mean is given as;

Mean = \frac{\textup{Sum of all the data values}}{\textup{Total number of data value}}

or

⇒ Mean = \frac{\textup{3753}}{\textup{33}}

or

⇒ Mean = 113.72

Hence,

The estimator of 113.72 is point estimate used for the  conceptual population of all first-graders in this school

5 0
3 years ago
The equation of a line is y=-2.5x+3. Which one of these points lies on this line?
lakkis [162]
D is the correct answer. Since this is an equation, equation means both side are equal. So if you put each point in place of y and x and do the math on the left side, the final result of that side has to be equal to the left one. Only (-2,2) follows this statement aka its a point on this line .
7 0
3 years ago
Ashley posts 17 status updates on her Facebook wall each day . Roberto posts 21 status updates on his Facebook wall each day .
shutvik [7]

Let x be the number of days.  

If Ashley posts 17 status updates each day, then after x days Ashley posts 17x status updates.

If Roberto posts 21 status updates each day, then after x days Roberto posts 21x status updates.

Part A. The combined number of posts for Ashley and Roberto after x days is:

17x+21x.

Part B. The difference between number of posts for Ashley and Roberto after x days is:

21x-17x.

4 0
3 years ago
Read 2 more answers
Other questions:
  • (x^3 + 6x^2 + 3x + 1 ) ÷ (x - 2) synthetic division
    8·1 answer
  • If 9100 dollars is invested at an interest rate of 8 percent per year, find the value of the investment at the end of 5 years fo
    12·1 answer
  • Two groups of students order burritos and tacos at a local restaurant. One order of 3 burritos and 4 tacos coast 11.33. The othe
    5·1 answer
  • In the rhombus m 1=18x m 2=x+y and m 3=30z. Find the value of x+y+z
    13·1 answer
  • Write 23 in significant notation​
    7·2 answers
  • Tina kept a record of the amount of rainfall at her house each month. January had 3.331 February had 3.133 March had 3.313 and A
    12·1 answer
  • What is the equation of the line shown on the graph? (-3,1) (2,-4)
    15·1 answer
  • The radius of a circle is 3.8 feet. Find the diameter.
    7·2 answers
  • Select the correct answer. Which piecewise function is shown on the graph?
    5·2 answers
  • How many total atoms of Aluminum (Al) are represented:<br> 4Al3O3
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!