Solve for x: 4.23x + 1 = 17.8929 A. 0 B. 14.6629 C. 5.23 D. 6.23 PLEASE HELP!!!
1 answer:
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Answer:
22 more gallons.
Step-by-step explanation:
Given:
Car A's fuel efficiency is 34 miles per gallon of gasoline.
Car B's fuel efficiency is 23 miles per gallon of gasoline.
Question asked:
At those rates, how many more gallons of gasoline would car B consume than car A on a 1,564 miles trip?
Solution:
<u>Car A's fuel efficiency is 34 miles per gallon of gasoline.</u>
<u>By unitary method:</u>
Car A can travel 34 miles in = 1 gallon
Car A can travel 1 mile in =
Car A can travel 1564 miles in =
<u>Car B's fuel efficiency is 23 miles per gallon of gasoline.</u>
Car B can travel 23 miles in = 1 gallon
Car B can travel 1 mile in =
Car B can travel 1564 mile in =
We found that for 1564 miles trip Car A consumes 46 gallons of gasoline while Car B consumes 68 gallons of gasoline that means Car B consumes 68 - 46 = 22 gallons more gasoline than Car A.
Thus, Car B consumes 22 more gallons of gasoline than Car A consumes.
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Answer:
a = 18.15
Step-by-step explanation:
Combine like terms on the left side of the equation first. Add 7 and 42, then subtract 32 from the answer you get, then subtract 32 from that answer. This is going by order of PEMDAS.
Remember PEMDAS: (numbers 3 & 4 and numbers 5 & 6 are solved from left to right)
- Parentheses
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
After combining like terms on the left side, you get -15. Now combine like terms on the right side of the equation by adding 14.3 and 7.
Get -2a alone by subtracting 21.3 from both sides.
Divide both sides by -2.
In this equation, a should equal .