(MIDDLE SCHOOL MATH) Please help!

Two sides of a triangle are equal in length and double the length of the shortest side. The perimeter of the triangle is 36 inch

Lostsunrise [7]

To solve this, you can set up an equation. Make the length of the shortest side x, so the 2 sides double the length will equal 2x. Since they all equal the perimeter of 36, do x + 2x + 2x =36. These values all represent the sides(2 longer, one short). Combine like terms to get 5x=36 then divide by 5 to find the value of x. x=7.2in meaning the shorter side is 7.2 inches while the longer sides are both 14.4 inches each since they are double in size.

3 0

4 years ago

Q26. Division A has 15 students and division B has 20 students. Average score of students in division A is greater by 2 as compa

Romashka [77]

Step-by-step explanation:

Let a be the total score of Div. A

Let b be the total score of Div. B

given,

$\frac{a}{15} - \frac{b}{20} = 2$

as equation 1.

and

$b - a = 160 \\ - a + b = 160$

as equation 2.

Now multiply equation 2 by 1/20 to eliminate b to solve for a.

$( - a)( \frac{1}{20} ) + (b)( \frac{1}{20} ) = ( \frac{1}{20} )(160) \\ - \frac{a}{20} + \frac{b}{20} = 8$

take this new equation as equation 3.

now we will use equation 1 + equation 3 to eliminate b to solve for a.

$( \frac{a}{15} + ( - \frac{a}{20} )) + ( - \frac{b}{20} + \frac{b}{20} ) = 2 + 8 \\ \frac{a}{60} = 10 \\ a = 60 \times 10 \\ = 600$

Div.A total score = 600

Average Score = Total Score / Number of students.

$\frac{600}{15} \\ = 40$

3 0

3 years ago

Is anyone willing to help me with my math homework? i don’t really understand it :/

____ [38]

I’ll try to tutor you. What’s it about?

6 0

3 years ago

Read 2 more answers

There are 98 flowers in the bride's bouquet. If 25 of the flowers are roses, approximately what percent of the flowers in the bo

Setler [38]

Answer:

About 75 % are not roses.

Step-by-step explanation:

3 0

3 years ago

PLEASE HELP ILL MARK YOU BRAINLIEST!!!!! 75 POINTS Use the function f(x) = 2x2 − 5x + 3 to answer the questions. Part A: Complet

andrew-mc [135]

Answer:

A. $(2x-3)(x-1)$

B. $(1,0) \\(1.5,0)$

$2x^2-5x+3\\\frac{5(+ or -)\sqrt{(-5)^2-(4)(2)(3)} }{2(2)} \\\frac{5(+ or -)\sqrt{25-24} }{4}\\\frac{5(+ or -)\sqrt{1} }{4}\\ \frac{5(+ or -)1 }{4}\\\frac{5+1}{4} or \frac{5-1}{4} \\ \frac{6}{4} =1.5 and \frac{4}{4} =1$

C. Both sides will continue to increase as they go because this is an even degree quadratic equation.

D. You use the two x-intercepts to make sure it is in the correct area and since we know the end behavior all you'd have to assume is that it continues to go up so any negative answers you may accidentally receive would be incorrect.

3 0

3 years ago