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Leviafan [203]
3 years ago
15

an emu is 57 inches tall 75 inchess less than an 6 times height of an kakapoo what is the height of a kakapoo in inches

Mathematics
1 answer:
vredina [299]3 years ago
8 0

We can solve the following equation: 5 x - 70 = 60, where x is the height of a kakapo in inches : 5 x - 70 + 70 = 60 + 70 ( we will add 70 to the both sides of an equation ), 5 x = 130, x = 130 : 5, x = 26 inches. We can prove it: 26 * 5 - 70 = 130 - 70 = 60 inches ( the height of an emu in inches ). Answer: The height of a kakapo is 26 inches.

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Will mark brainliest to whoever can answer 10-15
fgiga [73]

f(x) = x² + 7

g(x) = -3x + 1

h(x) = 12/x

j(x) = 2x + 9

a.  g(10) = -3(10) + 1 = -20

b. f(3) = 3² + 7 = 9 + 7 = 16

c. h(-2) = 12/(-2) = -6

d. j(7) = 2(7) + 9 = 23

e. h(a) = 12/a

f. g(b+c) = -3(b+c) + 1 = -3b - 3c + 1

g. f(h(x)) = f(12/x) = (12/x)² + 7 = 7 + 144/x²

h. 16 = g(x) = -3x + 1,    -3x = 15,   x = -5

i. -2 = h(x) = 12/x,    x = 12/(-2),  x = -6

j.  23 = f(x) = x²+7,   16=x²,   x=±4

4 0
3 years ago
Particle travels along a circular path that has a radius of 3 feet. The angular velocity of the particle is 18 radians per minut
Gala2k [10]
We know that

[length of a circumference ]=2*pi*r
for r=3 ft

[length of a circumference ]=2*pi*3-----------> 18.84 ft

<span>The angular velocity of the particle is 18 radians per minute.

if 2pi radians  (full circle)------------------> 18.84 ft
18 radians----------------------------------> X
X=18*18.84/(2*pi)---------> X=54 ft
so
</span>The linear velocity of the particle is 54 ft/minute

the answer is
54 ft/min
6 0
3 years ago
Read 2 more answers
What is the LCM of 30 and 42
IgorC [24]
the least common multiple is 210
5 0
3 years ago
Read 2 more answers
1. A gym has 200 members who pay $30 per month for unlimited use of the gym’s equipment. A survey of the members indicates that
choli [55]

200 members pay $30 each
Current revenue = 200 x $30
= $6000

For each $5 increase in  fee, 20 members will leave
For i number of $5 increase, 20i members will leave
New number of members = 200 - 20i

For i number of $5 increase, new fee = 30 + 5i

Therefore, new revenue = (200 - 20i) x (30 + 5i)
= 200(30 + 5i) - 20f(30 + 5i)
= 6000 + 1000i - 600i - 100i²
= 6000 + 400i - 100i²

In the form of a quadratic equation, 
-100i² + 400i + 6000
R(i) = -100i² + 400i + 6000

This is not our answer yet.
We are told to write a quadratic inequality for what numbers of $5 fee increases will the revenue from fees actually be less than its current value

Current value = 6000

Therefore, we are looking for i, when R(i) < 6000
Remember, R(i) = -100i² + 400i + 6000

Therefore,
R(i) < 6000 = -100i² + 400i + 6000 < 6000

We are to solve the quadratic inequality,
-100i² + 400i + 6000 < 6000

⇒ -100i² + 400i < 0 (Subtract 6000 from both sides)
⇒ 400i < 100i²  (Add 100i to both sides)
⇒ 4i < i² (Divide both sides by 100)
⇒ 4 < i (Divide both sides by i)

4 < i can be rewritten as i > 4

Therefore, for more than 4 numbers of <span>$5 increase in the fees, the revenue from fees will actually be less than its current value.</span>

6 0
3 years ago
Geno started to evaluate 90 − (18 + −2)(−3), as shown. What should he do next?
Allisa [31]
Simplify (18+-2) to 90-(16)(-3)
Multiply (16)(-3) -> -48
Simplify 90-48
Answer is 42
4 0
3 years ago
Read 2 more answers
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