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worty [1.4K]
4 years ago
6

2loge3 + loge x - loge2 = loge3 Solve for x

Mathematics
1 answer:
Readme [11.4K]4 years ago
7 0
2\ln 3+\ln x-\ln 2=\ln 3\\
\ln x=-\ln 3+\ln 2\\
\ln x=\ln \dfrac{1}{3}+\ln 2\\
\ln x=\ln \dfrac{2}{3}\\
x=\dfrac{2}{3}
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Mario draws a scale drawing that includes a ladybug. The actual ladybug is 8 millimeters long. The ladybug in Mario's drawing is
solniwko [45]
Scale factor shows by how much the original model has been multiplied or divided by to get the measurements of the drawing .
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4 years ago
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3 years ago
What is the solution to the linear equation? x – StartFraction 2 Over 3 EndFraction x minus StartFraction one-half EndFraction e
Anton [14]

<em>Your question is not well presented</em>

Question:

What is the solution to the linear equation?

x - \frac{2}{3}x - \frac{1}{2} = \frac{1}{3} + \frac{5}{6}x

Answer:

x = \frac{-5}{3}

Step-by-step explanation:

Given

x - \frac{2}{3}x - \frac{1}{2} = \frac{1}{3} + \frac{5}{6}x

Required

Simplify

x - \frac{2}{3}x - \frac{1}{2} = \frac{1}{3} + \frac{5}{6}x

Add \frac{1}{2} to both sides

x - \frac{2}{3}x - \frac{1}{2} + \frac{1}{2} = \frac{1}{3} + \frac{5}{6}x + \frac{1}{2}

x - \frac{2}{3}x = \frac{1}{3} + \frac{5}{6}x + \frac{1}{2}

Subtract \frac{5}{6}x from both sides

x - \frac{2}{3}x - \frac{5}{6}x= \frac{1}{3} + \frac{5}{6}x + \frac{1}{2} - \frac{5}{6}x

x - \frac{2}{3}x - \frac{5}{6}x= \frac{1}{3} + \frac{1}{2} + \frac{5}{6}x- \frac{5}{6}x

x - \frac{2}{3}x - \frac{5}{6}x= \frac{1}{3} + \frac{1}{2}

Take LCMs

\frac{6x - 4x -5x}{6}= \frac{2+3}{6}

\frac{-3x}{6}= \frac{5}{6}

Multiply both sides by 6

6 * \frac{-3x}{6}= \frac{5}{6} * 6

-3x= 5

Divide both sides by -3

\frac{-3x}{-3}= \frac{5}{-3}

x = \frac{5}{-3}

x = \frac{-5}{3}

5 0
4 years ago
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Julli [10]
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Therefore:

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Equation No. 2 -
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y = ( 2x - 4 ) / 5

ANSWER:
x = 32°
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3 years ago
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