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ddd [48]
3 years ago
13

Shaunda answered 86% of the questions on her test correctly. If there were 50 questions on the test, how many did she NOT answer

correctly?
pls help
Mathematics
2 answers:
Arada [10]3 years ago
8 0

Answer: 7 Answers Incorrect

Step-by-step explanation:

86% may be written as (86/100) or as 0.86.

Since "it's a ratio (sic.) problem," then:

                 86/100 = correct/50

                correct = (86/100)*50       (multiply both sides by 50)

                correct = 43

And, 50-43 = 7 incorrect

solong [7]3 years ago
4 0
7 questions were wrong

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My score in math is a 69 pls help
Xelga [282]

Answer:

okay

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
"If 5 is decreased from double Joe's weight, the result is 230. What is Joe's weight?"<br> 30
Gala2k [10]

Answer:

117.5 or 235/2

Step-by-step explanation:

We can set up an equation for this problem:

Lets Joe's weight be x

then:

2x -5 = 230

therefore:

2x = 235

x = 117.5 or 235/2

3 0
3 years ago
The flaplike lateral wall of each atrium is called the
pantera1 [17]
You mean like the tricuspid and mitral (bicuspid) valves?
6 0
3 years ago
Read 2 more answers
A bag contains six red and ten black marbles if you pick a marble from the bag what is the probability that the marble will be b
dimulka [17.4K]

Answer:

125

Step-by-step explanation:

The total number of marbles is 6+10 = 16

P (black) = black / total

               = 10/16  = 5/8

With 200 draws, take the probability of P(black) times 200 since the marble is returned each time

200 * (5/8) = 125

We would expect to get 125 black marbles

6 0
3 years ago
In a sample of 70 stores of a certain​ company, 62 violated a scanner accuracy standard. It has been demonstrated that the condi
uysha [10]

Answer:

We need at least 243 stores.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error of the interval is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

For this problem, we have that:

n = 70, p = \frac{62}{70} = 0.886

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

Determine the number of stores that must be sampled in order to estimate the true proportion to within 0.04 with 95​% confidence using the​ large-sample method.

We need at least n stores.

n is found when M = 0.04. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.04 = 1.96\sqrt{\frac{0.886*0.114}}{n}}

0.04\sqrt{n} = 1.96\sqrt{0.886*0.114}

\sqrt{n} = \frac{1.96\sqrt{0.886*0.114}}{0.04}

(\sqrt{n})^{2} = (\frac{1.96\sqrt{0.886*0.114}}{0.04})^{2}

n = 242.5

Rounding up

We need at least 243 stores.

5 0
2 years ago
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