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ddd [48]
3 years ago
13

Shaunda answered 86% of the questions on her test correctly. If there were 50 questions on the test, how many did she NOT answer

correctly?
pls help
Mathematics
2 answers:
Arada [10]3 years ago
8 0

Answer: 7 Answers Incorrect

Step-by-step explanation:

86% may be written as (86/100) or as 0.86.

Since "it's a ratio (sic.) problem," then:

                 86/100 = correct/50

                correct = (86/100)*50       (multiply both sides by 50)

                correct = 43

And, 50-43 = 7 incorrect

solong [7]3 years ago
4 0
7 questions were wrong

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If the temperature dropped to -16 degrees what is the absolute value?
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What is one thousand five hundred divided by five equal
Vikki [24]

Answer: 300

We know that 5×3=15. Since we are trying to get 1500 we Multiply 300×5 and get 1500.

<u>How do we know?</u>

  • As you can see if you cross out 2 of the 0 in 300 you have 3×5. When you multiply it you get 15.
  • Also if you cross out 1 of the 0 in 300 you have 30×5. When you multiply that you get 150.

As you see when you still multiply either of those problems you have 15 in it. So we should know 300×5=1500.

Note: We can also multiply 500×3 and get 1500. You still get the same answer but just switched numbers.

5 0
3 years ago
Read 2 more answers
A particle moves along a line with acceleration a (t) = -1/(t+2)2 ft/sec2. Find the distance traveled by the particle during the
amm1812

Answer:

s(t)=(ln|7|+ln|2|)\,ft

Step-by-step explanation:

Acceleration is second derivative of distance and are related as:

a(t)=\frac{d^2s}{dt^2}\\\\\frac{d^2s}{dt^2}=\frac{-1}{(t+2)^2}\\

Integrating both sides w.r.to t

v(t)=\frac{ds}{dt}=\frac{1}{t+2} +C\\

Using initial value

v(0)=\frac{1}{2}\\\\\frac{1}{2}=\frac{1}{0+2} +C\\\\C=0\\\\\frac{ds}{dt}=\frac{1}{t+2}

We have to calculate the distance covered in time interval [0,5], so:

\int\limits^5_0 \frac{ds}{dt}=\int\limits^5_0 {\frac{1}{t+2}} \, dt\\\\s(t)=[ln|t+2|]^5_0\\\\s(t)=ln|5+2|+ln|0+2|\\\\s(t)=(ln|7|+ln|2|)\,ft

3 0
3 years ago
the weights of ten cats in pounds are 14, 10, 11, 9, 12, 8, 8, 10, 7, and 10. what is the mean absolute deviation of the weights
BabaBlast [244]

Answer:

HOW TO DO STEP BY STEP:)

Original set ={14, 10, 11, 9, 12, 8, 8, 10, 7,10}

n = 8 is the number of values in that set above

Add up the values 12+11+7+10+10+11+6+8+14+8 = 97

Divide that sum by n = 8 to get 97/8 = 12. So the mean = 12

For each value in the original set {14, 10, 11, 9, 12, 8, 8, 10, 7,10} subtract off the mean = 12. Apply the absolute value to ensure the result is positive or zero

|x - mean| = |14 - 12| = -2

|x - mean| = |10 - 12| = 2

|x - mean| = |11- 12| = 1

|x - mean| = |9 - 12| = 3

|x - mean| = |12 - 12| =0

|x - mean| = |8 - 12| = 4

|x - mean| = |8 - 12| = 4

|x - mean| = |10 - 12| =2

|x - mean| = |7 - 12| = 5

|x - mean| = |10 - 12| = 2

The set of results we get are: {-2,2,1,3,4,4,2,5,2 } -2,2,1,3,4,4,2,5,= 21, then we divide 21 that over n = 12 (21/12) to get  = 1.75

Therefore the mean absolute deviation (MAD) is 1.75

7 0
3 years ago
Read 2 more answers
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