Question

Which is the equation of a parabola with vertex (0, 0), that opens to the left and

Answer 1

Answer:

Step-by-step explanation:

I'm going to guess that the square  exponents are on the top y's   only?   then answer b) looks good

Answer 2

Answer:

b. y^2 = -12x

Step-by-step explanation:

The general form for  the given parabola is y^2 = -4ax where the focus is at (-a, 0). The focal width is 4a which in this case = 12.