Answer:
53.3 yards
Step-by-step explanation:
you just have to divide 160 by 3 to get it in yards
Answer:
A. H0: p = 0.67; H1: p < 0.67
A. The standard normal, since np > 5 and nq > 5.;
Test statistic = - 0.397 ;
Pvalue = 0.3457;
D. At the α = 0.05 level, we fail to reject the null hypothesis and conclude the data are not statistically significant.
B. There is insufficient evidence at the 0.05 level to conclude that the true proportion of women athletes who graduate is less than 0.67.
Step-by-step explanation:
p = 0.67 ; q = 1 - p = 1 - 0.67
Sample size, n = 36
x = 23
Test for normality :
(36*0.67) = 24.12
(36 * (1-0.67)) = 11.88
For a normal distribution :
np ≥ 5 and n(1 - p) ≥ 5
The hypothesis :
H0 : p = 0.67
H1 : p < 0.67
The Test statistic :
Z = (phat - p) / √[(p(1 -p))/n]
Phat = x / n = 23 / 36
Z = ((24/36) - 0.67)) / √[(0.67(1 -0.67))/36]
Z = - 0.031 / 0.0783687
Z = - 0.396983
Z = - 0.397
Usong the Pvalue from Z calculator ;
Pvalue of Z = 0.3457
If Pvalue < α ; Reject H0 ; If otherwise, Fail to reject H0
Answer:
= 0.786885 dollars per gallon
Step-by-step explanation:
We want a unit rate where
1 is in the denominator,
so we divide top and bottom by 61
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