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4 years ago

6

A 26’ long painting is how many yards long?

1 answer:

blsea [12.9K]4 years ago

4 0

A 26' long painting is equal to 8.7 yards.
Hope this helps!

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If a radius of a circle is 12 feet, what is the area and perimeter of the circle?

Vesna [10]

Area of a circle=πr²
area of this cirlce=π*(12 ft)²=144π ft²≈452.39 ft².

answer 1= the area of this circle is 452.39 ft².

Perimeter of a circle=2πr.
Perimeter of this cirlce=2π(12 ft)=24π ft≈75.4 ft

<span>answer 2= the perimeter of this cirlce is 75.4 ft.</span>

4 0

3 years ago

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Determine the length the 6 meter side and the 12 meter side will be in the drawing.

vladimir2022 [97]

Answer:

x=2,x=4

So, the 6-meter side will be 2 centimeters and the 12-meter side will be 4 centimeters in the drawing.

Step-by-step explanation:

Solve for x by using cross multiplication

6=3x

x=2

12=3x

x=4

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3 years ago

CAN SOMEONE HELP? ⚠️ I WILL GIVE ANY POINTS PLEASE I AM SO CONFUSED EVEN IF ITS JUST THE ANSWER I HAVE SO MUCH TO DO IF SOMEONE

gogolik [260]

Answer:
X = 3

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2 years ago

Williiam lost 25% of his marble,gave 1/6 of the remainder to his.Brother and had 120 marbles left.How many marbles did he have a

bija089 [108]

Answer:

Number of marbles with Williams at the starting = 192

Step-by-step explanation:

Let total number of marbles with Williams = m

He lost marbles = 25% of the total number

= $\frac{25}{100}\times m$

= $\frac{m}{4}$

Remaining marbles with Williams = m - $\frac{m}{4}$

= $\frac{3m}{4}$

He gave marbles to his brother = $\frac{1}{6}$ th of the remaining marbles

= $\frac{1}{6}\times \frac{3m}{4}$

= $\frac{m}{8}$

Remaining marbles after giving marbles to his brother = 120

Therefore, $\frac{3m}{4}-\frac{m}{8}=120$

$\frac{6m}{8}-\frac{m}{8}=120$

$\frac{5m}{8}=120$

m = $\frac{120\times 8}{5}$

m = 192

Number of marbles with Williams at the starting = 192

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3 years ago

Find the measure of arc UT Given a.168<br> b.192<br> c.84<br> d.96

Juliette [100K]

Answer:

is there supossed to be a picture?

Step-by-step explanation:

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3 years ago

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