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3 years ago

10

the width of a rectangle is x centimetres and its length is (x+ 2) cm. Write down an expression for the perimeter of the rectang

le, giving your answer in its simplest form

2 answers:

klasskru [66]3 years ago

7 0

Answer: P = 4(x + 1)

Step-by-step explanation:

abruzzese [7]3 years ago

3 0

Perimeter = length + length + width + width

P= (x + 2) + (x + 2) + x + x
P = x + 2 + x + 2 x + x
P= 4x + 4

Some teachers then want you to pull out the common factor of 4. If yours does, it’s P = 4(x + 1)

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Fulton Gardens buys 6,300 flower bulbs. If 70 bulbs can be planted in each flower bed, how many flower beds are needed to plant

ki77a [65]

Answer:

90

Step-by-step explanation:

6300/70=90

6 0

3 years ago

The weight of a Great blue heron, a type of bird, can grow to around 4 pounds, but can vary. Let W be a random variable that rep

hammer [34]

Answer:

10 ≥ w ≥ 9 ( ? )

Step-by-step explanation:

the probability that a Great blue heron is at least 9 pounds, but no more than 10 pounds -> w= weight of great blue heron

w is at lest 9 pound's -> w ≥ 9

w is no more than 10 pound's -> w ≥ 10

w ≥ 9 ( + ) w ≥ 10 = 10 ≥ w ≥ 9

6 0

4 years ago

June needs 45 gallons of punch for a party and has 2 different coolers to carry it in. The bigger cooler is 5 times as large as

mixer [17]

Answer:

The capacity of smaller cooler = 7.5 gallons

The capacity of bigger cooler = 37.5 gallons

Step-by-step explanation:

Let smaller cooler's capacity be x gallons

Hence

Larger cooler's capacity will be 5x gallons

Together, they will hold 45 gallons, thus we can write:

x + 5x = 45

Solving:

x + 5x = 45

6x = 45

x = 45/6 = 7.5

And 5x = 5(7.5) = 37.5

The capacity of smaller cooler = 7.5 gallons

The capacity of bigger cooler = 37.5 gallons

4 0

3 years ago

May someone help me with this problem?

Katyanochek1 [597]

Answer:

$a. \: \: \frac{ {4x}^{6} }{ {y}^{3} } \\$

$b. \: \: \frac{ {8x}^{3} }{ {y}^{ 1\frac{1}{3} } } \\$

Step-by-step explanation:

<h3>a. </h3>

${( {4x}^{ - 2} y)}^{ - 3} \\ {4x}^{ - 2 \times - 3} \: \: {y}^{1 \times - 3} \\ {4x}^{6} {y}^{ - 3} \\ \frac{ {4x}^{6} }{ {y}^{3} } \\$

<h3>b.</h3>

${( {8x}^{6} {y}^{ - 3}) }^{ \frac{1}{2} } \\ {8x}^{6 \times \frac{1}{2} } \: \: {y}^{ - 3 \times \frac{1}{2} } \\ {8x}^{3} {y}^{ - \frac {3}{2} } \\ \frac{ {8x}^{3} }{ {y}^{ 1\frac{1}{3} } } \\$

7 0

2 years ago

<img src="https://tex.z-dn.net/?f=%20%20%5Csf%20%5Chuge%7B%20question%20%5Chookleftarrow%7D" id="TexFormula1" title=" \sf \huge

BabaBlast [244]

$\underline{\bf{Given \:equation:-}}$

$\\ \sf{:}\dashrightarrow ax^2+by+c=0$

$\sf Let\:roots\;of\:the\: equation\:be\:\alpha\:and\beta.$

$\sf We\:know,$

$\boxed{\sf sum\:of\:roots=\alpha+\beta=\dfrac{-b}{a}}$

$\boxed{\sf Product\:of\:roots=\alpha\beta=\dfrac{c}{a}}$

$\underline{\large{\bf Identities\:used:-}}$

$\boxed{\sf (a+b)^2=a^2+2ab+b^2}$

$\boxed{\sf (√a)^2=a}$

$\boxed{\sf \sqrt{a}\sqrt{b}=\sqrt{ab}}$

$\boxed{\sf \sqrt{\sqrt{a}}=a}$

$\underline{\bf Final\: Solution:-}$

$\\ \sf{:}\dashrightarrow \sqrt{\alpha}+\sqrt{\beta}$

$\bull\sf Apply\: Squares$

$\\ \sf{:}\dashrightarrow (\sqrt{\alpha}+\sqrt{\beta})^2= (\sqrt{\alpha})^2+2\sqrt{\alpha}\sqrt{\beta}+(\sqrt{\beta})^2$

$\\ \sf{:}\dashrightarrow (\sqrt{\alpha}+\sqrt{\beta})^2 \alpha+\beta+2\sqrt{\alpha\beta}$

$\bull\sf Put\:values$

$\\ \sf{:}\dashrightarrow (\sqrt{\alpha}+\sqrt{\beta})^2=\dfrac{-b}{a}+2\sqrt{\dfrac{c}{a}}$

$\\ \sf{:}\dashrightarrow \sqrt{\alpha}+\sqrt{\beta}=\sqrt{\dfrac{-b}{a}+2\sqrt{\dfrac{c}{a}}}$

$\bull\sf Simplify$

$\\ \sf{:}\dashrightarrow \underline{\boxed{\bf {\sqrt{\boldsymbol{\alpha}}+\sqrt{\boldsymbol{\beta}}=\sqrt{\dfrac{-b}{a}}+\sqrt{2}\dfrac{c}{a}}}}$

$\underline{\bf More\: simplification:-}$

$\\ \sf{:}\dashrightarrow \sqrt{\alpha}+\sqrt{\beta}=\dfrac{\sqrt{-b}}{\sqrt{a}}+\dfrac{c\sqrt{2}}{a}$

$\\ \sf{:}\dashrightarrow \sqrt{\alpha}+\sqrt{\beta}=\dfrac{\sqrt{a}\sqrt{-b}+c\sqrt{2}}{a}$

$\underline{\Large{\bf Simplified\: Answer:-}}$

$\\ \sf{:}\dashrightarrow\underline{\boxed{\bf{ \sqrt{\boldsymbol{\alpha}}+\sqrt{\boldsymbol{\beta}}=\dfrac{\sqrt{-ab}+c\sqrt{2}}{a}}}}$

5 0

2 years ago

Read 2 more answers