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s344n2d4d5 [400]
3 years ago
14

HELPHELPHELPHELPHELPHELPPPPP​

Mathematics
2 answers:
Makovka662 [10]3 years ago
6 0

Answer:

pretty sure its -2,3 :)

Step-by-step explanation:

dimaraw [331]3 years ago
5 0

Answer:

(-2,3)

Step-by-step explanation:

Coordinates of Points

A point is the basic relationship displayed on a graph. Each point is defined by a pair of numbers containing two coordinates.

A coordinate is one of a set of numbers used to identify the location of a point on a graph.

Identifying the x-coordinate

The x-coordinate of a point is the value that tells you how far from the origin the point is on the horizontal, or x-axis. To find the x-coordinate of a point on a graph:

- Draw a straight line from the point directly to the x-axis.

- The number where the line hits the x-axis is the value of the x-coordinate.

Identifying the y-coordinate

Now that you know how to find the x-coordinate of a point, you have to be able to find the y-coordinate.

The y-coordinate of a point is the value that tells you how far from the origin the point is on the vertical, or y-axis. To find the y-coordinate of a point on a graph:

- Draw a straight line from the point directly to the y-axis.

- The number where the line hits the axis is the value of the y-coordinate.

Notation for Identifying Points

Once you have the coordinates of a point you can use the ordered pair notation for labeling points. The notation is simple. Points are identified by stating their coordinates in the form of (x, y). Note that the x-coordinate always comes first.

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Refer to the map shown in Exercise 2. If m∠1 is 64˚, what is the measure of ∠2?
zmey [24]
<h2>Explanation:</h2><h2></h2>

Hello! Remember you have to write complete questions in order to get good and exact answers. Here you haven't provided any figure, so I'll assume m∠1 and m∠2 are complementary angles. Angles that add up to 90° are called complementary angles. In this case, we know m∠1 and want to know m∠2. Thus, we can establish the following formula:

m∠1 + m∠2 = 90°

Isolating m∠2:

m∠2 = 90° -  m∠1

m∠2 = 90° -  64

m∠2 = 26°

5 0
3 years ago
If A and B are mutually exclusive events, with P(A) = 0.19 and P(B) = 0.27, what is P(A or B)?
insens350 [35]
I believe it's D. 0.46

Hope I helped! ( Smiles )
8 0
3 years ago
Read 2 more answers
What’s the length of the segments variable expressions ??
maxonik [38]

Answer:

EF=9\ units

Step-by-step explanation:

we know that

The <u><em>Trapezoid Mid-segment Theorem</em></u> states that: A line connecting the midpoints of the two legs of a trapezoid is parallel to the bases, and its length is equal to half the sum of lengths of the bases

so In this problem

EF=\frac{1}{2}[AD+BC]

substitute the given values

x=\frac{1}{2}[(x-6)+(2x-3)]

x=\frac{1}{2}[3x-9]

2x=(3x-9)\\3x-2x=9\\x=9

so

AD=x-6=9-6=3\ units

EF=x=9\ units

BC=2x-3=2(9)-3=15\ units

4 0
3 years ago
Does anyone know how to do this? I’m confused
nikklg [1K]

Answer:

cos(θ)

Step-by-step explanation:

Para una función f(x), la derivada es el límite de  

h

f(x+h)−f(x)

​

, ya que h va a 0, si ese límite existe.

dθ

d

​

(sin(θ))=(  

h→0

lim

​

 

h

sin(θ+h)−sin(θ)

​

)

Usa la fórmula de suma para el seno.

h→0

lim

​

 

h

sin(h+θ)−sin(θ)

​

 

Simplifica sin(θ).

h→0

lim

​

 

h

sin(θ)(cos(h)−1)+cos(θ)sin(h)

​

 

Reescribe el límite.

(  

h→0

lim

​

sin(θ))(  

h→0

lim

​

 

h

cos(h)−1

​

)+(  

h→0

lim

​

cos(θ))(  

h→0

lim

​

 

h

sin(h)

​

)

Usa el hecho de que θ es una constante al calcular límites, ya que h va a 0.

sin(θ)(  

h→0

lim

​

 

h

cos(h)−1

​

)+cos(θ)(  

h→0

lim

​

 

h

sin(h)

​

)

El límite lim  

θ→0

​

 

θ

sin(θ)

​

 es 1.

sin(θ)(  

h→0

lim

​

 

h

cos(h)−1

​

)+cos(θ)

Para calcular el límite lim  

h→0

​

 

h

cos(h)−1

​

, primero multiplique el numerador y denominador por cos(h)+1.

(  

h→0

lim

​

 

h

cos(h)−1

​

)=(  

h→0

lim

​

 

h(cos(h)+1)

(cos(h)−1)(cos(h)+1)

​

)

Multiplica cos(h)+1 por cos(h)−1.

h→0

lim

​

 

h(cos(h)+1)

(cos(h))  

2

−1

​

 

Usa la identidad pitagórica.

h→0

lim

​

−  

h(cos(h)+1)

(sin(h))  

2

 

​

 

Reescribe el límite.

(  

h→0

lim

​

−  

h

sin(h)

​

)(  

h→0

lim

​

 

cos(h)+1

sin(h)

​

)

El límite lim  

θ→0

​

 

θ

sin(θ)

​

 es 1.

−(  

h→0

lim

​

 

cos(h)+1

sin(h)

​

)

Usa el hecho de que  

cos(h)+1

sin(h)

​

 es un valor continuo en 0.

(  

h→0

lim

​

 

cos(h)+1

sin(h)

​

)=0

Sustituye el valor 0 en la expresión sin(θ)(lim  

h→0

​

 

h

cos(h)−1

​

)+cos(θ).

cos(θ)

5 0
3 years ago
Read 2 more answers
Which description is paired with it's correct expression?​
EleoNora [17]
Two less than the quotient of a number cubed and four, increased by eight
six times the difference of five and a number squared;
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