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Alex787 [66]
2 years ago
5

Find x and y for this triangle

Mathematics
1 answer:
Feliz [49]2 years ago
7 0

Answer:

x = 1.25

x = 1.75

Step-by-step explanation:

I marked the points of this triangle in the attached image so it's easier to explain.

ΔABC is similar to ΔADE, and all pairs of corresponding sides are proportional as a result.

\frac{DE}{BC}=\frac{AD}{AB}=\frac{AE}{AC}

The length of the sides BC and DE is given, so I'll start with that and set it equal to the proportion between AB and AD.

\frac{DE}{BC}=\frac{AD}{AB}\\\\\frac{10}{8}=\frac{x+5}{5}\\\\10\times5=(x+5)\times8\\50=8x+40\\10=8x\\x=1.25

Now, you can do the exact same thing for y:

\frac{DE}{BC}=\frac{AE}{AC}\\\\\frac{10}{8}=\frac{y+7}{7}\\\\10\times7=(y+7)\times8\\70=8y+56\\14=8y\\y=1.75

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Answer:

B. Train B  

Step-by-step explanation:

We are told that Milford and Pinkerton is 300 miles away.

Train A leaves Milford at 10:00 am. There are 3 hours between 10:00 am to 1:00 pm. So let us find distance traveled by train A in 3 hours.

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\text{Distance traveled by train A}=90\frac{\text{ miles}}{\text{ hour}}\times 3\text{ hours}

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\text{Distance traveled by train A}=270{\text{ miles}

Since train A will cover 270 miles in 3 hours and distance between Milford and Pinkerton is 300 miles, therefore, train A will not arrive Pinkerton before 1:00 pm.

Since there are 5 hours between 8:00 am to 1:00 pm, so let us find distance traveled by train B in 5 hours.

\text{Distance traveled by train B}=70\frac{\text{ miles}}{\text{ hour}}\times 5\text{ hours}

\text{Distance traveled by train B}=70\times 5 \text{ miles}

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Since train B will cover 350 miles in 5 hours, therefore, train B will arrive Pinkerton before 1:00 pm and option B is the correct choice.

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Step-by-step explanation:

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