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balandron [24]
3 years ago
13

the amount of gasoline used by a car varies jointly as the distance travelled and the square root of the speed.Suppose a car use

d 25 liters on a 100 km trip at 100kph,about how many liters will it use on 1000 km trip at 64 kph?​
Mathematics
1 answer:
klemol [59]3 years ago
4 0

Answer:

200 litres

Step-by-step explanation:

let g be gasoline used, d the distance travelled and s the speed, then the equation relating the quantities is

g = kd\sqrt{s} ← k is the constant of variation

To find k use g = 25, d = 100 and s = 100, then

25 = k × 100 × \sqrt{100} = k × 100 × 10 = 1000k ( divide both sides by 1000 )

0.025 = k

g = 0.025d\sqrt{s} ← equation of variation

When d = 1000 and s = 64, then

g = 0.025 × 1000 × \sqrt{64} = 0.025 × 1000 × 8 = 200

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5 0
3 years ago
If b= 7, what is 1/3(2b+10)? Please help
goblinko [34]

Answer:8

Step-by-step explanation:

First, substitute 7 into the equation for b:

1/3(2x7+10)

Now, simplify using the order of operations:

1/3(14+10)

Then:

1/3 (24)

And you arrive at your answer:

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3 0
3 years ago
Read 2 more answers
Suppose that 45% of people have dogs. If two people are randomly chosen, what is the probability that they both have a dog
mylen [45]

Answer:

P(Dogs) = 0.2025

Step-by-step explanation:

Given

Proportion, p = 45\%

Required

Probability of two people having dog

First, we have to convert the given parameter to decimal

p = \frac{45}{100}

p = 0.45

Let P(Dogs) represent the required probability;

This is calculated as thus;

<em>P(Dogs) = Probability of first person having a dog * Probability of second person having a dog</em>

<em />

P(Dogs) = p * p

P(Dogs) = 0.45 * 0.45

P(Dogs) = 0.45^2

P(Dogs) = 0.2025

<em>Hence, the probability of 2 people having a dog is </em>P(Dogs) = 0.2025<em />

4 0
3 years ago
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Answer:

a. 20-degree

b. 110-degree

c.70-degree

d.50-degree

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2 years ago
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Answer:

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