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2 years ago

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Mathematics

1 answer:

sertanlavr [38]2 years ago

6 0

Answer: The system consists of parallel lines

Step-by-step explanation:

Given system of lines :

$y=\dfrac13x-4$

$3y-x=-7$

Substitute $y=\dfrac13x-4$ in $3y-x=-7$ , we get

$3(\dfrac13x-4)-x=-7\\\\\Rightarrow\ x-12-x=-7\\\\\Rightarrow\ -12=-7$ , which is not true.

That means , system has no solution.

i.e. they are representing parallel lines. [Parallel lines do not intersect and hence they do not have solution.]

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