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Pani-rosa [81]
3 years ago
5

The quotient of 37.2/6 is?

Mathematics
2 answers:
Dimas [21]3 years ago
4 0

Answer:

6.2

Just normal division

erma4kov [3.2K]3 years ago
4 0

Answer:

6.2

Step-by-step explanation:

you divide the 2

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Write each polynomial in standard form. Then give the leading coefficient. You may need to combine like terms before writing the
Bond [772]

Step-by-step explanation:

To write a polynomial in standard form, put the degree that are the greatest first

So here it would be

{x}^{5}   + 4 {x}^{3}  - 3 {x}^{2}  + 10

Remember constant are numbers that you learned back in elementary,

Numbers like 10,90,4,1,0,-3 etc.

Remember that constant are basically represented like this

k \times  {x}^{0}

For example, 10 is represented like

10 \times  {x}^{0}

Since 0 is the smallest degree possible, for a polynomial, constants are the last term of a polynomial in standard form

6 0
2 years ago
Evaluate C_n.xP^xQn-x For the given n=7, x=2, p=1/2
r-ruslan [8.4K]

Answer:

The value of given expression is \frac{21}{128}.

Step-by-step explanation:

Given information: n=7, x=2, p=1/2

q=1-p=1-\frac{1}{2}=\frac{1}{2}

The given expression is

C(n,x)p^xq^{n-x}

It can be written as

^nC_xp^xq^{n-x}

Substitute n=7, x=2, p=1/2 and q=1/2 in the above formula.

^7C_2(\frac{1}{2})^2(\frac{1}{2})^{7-2}

\frac{7!}{2!(7-2)!}(\frac{1}{2})^2(\frac{1}{2})^{5}

\frac{7!}{2!5!}(\frac{1}{2})^{2+5}

\frac{7\times 6\times 5!}{2\times 5!}(\frac{1}{2})^{2+5}

21(\frac{1}{2})^{7}

\frac{21}{128}

Therefore the value of given expression is \frac{21}{128}.

7 0
3 years ago
What is p?<br><br> 7 1/5+p+4 9/10+3 3/20=19 1/10
Yakvenalex [24]
ANSWER:
7 \frac{1}{5}+p+4 \frac{9}{10}+3 \frac{3}{20} =19 \frac{1}{10} \\ 7 \frac{4}{20}+p+4 \frac{18}{20} + 3 \frac{3}{20}=19 \frac{2}{20}  \\ p=19 \frac{2}{20}- (7 \frac{4}{20}+4 \frac{18}{20} + 3 \frac{3}{20})  \\ p=19 \frac{2}{20}-15 \frac{5}{20} \\ p=3\frac{17}{20}  
6 0
3 years ago
What is the explicit rule for this sequence?<br> -5, 15, – 45, 135, ...
hoa [83]

Answer:

Step-by-step explanation:

In a geometric sequence, consecutive terms differ by a common ratio. The formula for determining the nth term of a geometric progression is expressed as

an = a1r^(n - 1)

Where

a represents the first term of the sequence.

r represents the common ratio.

n represents the number of terms.

From the given sequence,

a1 = - 5

r = 15/- 5 = - 3

Therefore, the explicit rule for this sequence is

an = - 5(- 3)^n - 1

4 0
3 years ago
John works Monday to Friday. He buys his lunch on his way to work. Each day John buys a sandwich, a bottle of water and a bag of
kipiarov [429]

Complete question

Shop A _________________ shop B £3

Any sandwich - £2.85 ___ sandwich, water crisp

A bottle of water - 60p

A bag of crisp - 85p

Answer:

£6.50, John is incorrect

Step-by-step explanation:

Number of working days = 5 = number of days meal is purchased

Total cost per meal, shop A :

£(2.85 + 0.60 + 0.85) = £4.3

Total cost for the week = 4.3 * 5 = £21.50

Total cost per meal cost Shop B = £3

Total cost for the week = 3 * 5 = £15

Difference :

£21.50 - £15 = £6.50

Hence, Amount John saves by buying from shop B is £6.50

Numbe

4 0
2 years ago
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