All categories

2 years ago

Write a system of equations to describe the situation below, solve using elimination, and fill in the blanks.

Mathematics

2 answers:

ZanzabumX [31]2 years ago

8 0

Answer:

Step-by-step explanation:

Temka [501]2 years ago

8 0

Answer:

Admission prices are $3 per child and $4 per adult.

Step-by-step explanation:

Let the admission prices for children = x and for adults = y

When the pool had 10 children and 37 adults, which brought in $178

10x + 37y = 178 ⇒(1)

When the pool had 15 children and 23 adults, which brought in $137

15x + 23y = 137 ⇒(2)

Multiplying eq.(1) by 3 ⇒ 30x + 111y = 534 ⇒(3)

Multiplying eq.(2) by 2 ⇒ 30x + 46y = 274 ⇒(4)

Find eq.(3) - eq.(4)

∴ 111y - 46y = 534 - 274

∴ 65y = 260

∴ y = 260/65 = 4

By substitution with y at eq.(1)

10x + 37 * 4 = 178 ⇒ solve for x

10x = 178 - 37*4 = 30

∴ x = 30/10 = 3

So, Admission prices are $3 per child and $4 per adult.

You might be interested in

Do number 5 pleaseee

swat32

Answer:

Step-by-step explanation:

16 × 2 = 32

20 × 2 = 40

hshsjbdjidjeje

6 0

2 years ago

Solve the equation. Explain each step and identify the property used to reach each step.

Tom [10]

To isolate x, we will first subtract 0.8 from both sides.

0.6x + 0.8 = 1.4

-0.8 -0.8

0.6x = 0.6

Now all we have to do is divide both sides by 0.6, because it is the number besides x.

0.6x/0.6 = 0.6/0.6

x = 1

So you get the answer of x = 1.

7 0

2 years ago

Sphere and a cylinder have the same radius and height. The volume of the cylinder is 64 meters cubed.

Mrrafil [7]

Answer:

C. 128/3 meters cubed

Step-by-step explanation:

The volume of a cylinder is denoted by: $V=\pi r^2h$ , where r is the radius and h is the height. We know it's equal to 64, so we can set that equal to V:

$V=\pi r^2h$

$64=\pi r^2h$

We know that the sphere and cylinder have the same height and radius. However, the "height" of a sphere is actually the same as its diameter, which is twice its radius. Then, we can replace h in the above equation with 2r:

$64=\pi r^2h$

$64=\pi r^2*2r=2\pi r^3$

$\pi r^3=64/2=32$

Now, the volume of a sphere is denoted by: $V=\frac{4}{3} \pi r^3$ , where r is the radius. From above, we know that $\pi r^3=32$ , so we can plug this into the equation: