Please help I'm so confused pls look at picture
1 answer:
Answer and Step-by-step explanation:
Hello!
You are told to round the number to the nearest whole number.
That means if the decimal is lower than 5 in the tenths place, the number would round down, and if the decimal is equal to or higher than 5 in the tenths place, the number would round up.
is equal to 5.833. The number 8 is greater than 5, so the number rounds up to 6.
is equal to 6.111. The number 1 is less than 5, so the number rounds down to 6.
Now we have the equation n - 6 = 6.
We solve for n.
Add 6 to both sides.
n = 12
n is equal to 12.
#teamtrees #WAP (Water And Plant)
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Answer:
C
Step-by-step explanation:
We know it's direct variation using the direct variation equation.
Where k is the constant.
Since 7 times x is the y values,
Now we can substitute 7 into k of the direct variation equation.
Answers:
- Part a)
- Part b) 3
- Part c) 2.24
- Part d) 1.58
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Work Shown:
Part (a)
The origin is the point (0,0) which we'll make the first point, so let (x1,y1) = (0,0)
The other point is of the form (x,y) where y = x^2-3. So the point can be stated as (x2,y2) = (x,y). We'll replace y with x^2-3
We apply the distance formula to say...
We could expand things out and combine like terms, but that's just extra unneeded work in my opinion.
Saying is the same as writing d = sqrt(x^2-(x^2-3)^2)
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Part (b)
Plug in x = 0 and you should find the following
This says that the point (x,y) = (0,3) is 3 units away from the origin (0,0).
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Part (c)
Repeat for x = 1
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Part (d)
Graph the d(x) function found back in part (a)
Use the minimum function on your graphing calculator to find the lowest point such that x > 0.
See the diagram below. I used GeoGebra to make the graph. Desmos probably has a similar feature (but I'm not entirely sure). If you have a TI83 or TI84, then your calculator has the minimum function feature.
The red point of this diagram is what we're after. That point is approximately (1.58, 1.66)
This means the smallest d can get is d = 1.66 and it happens when x = 1.58 approximately.
