Answer:
I do not see a question here
Step-by-step explanation:
Pls add your question
Answer:
hope this helps and make me brainliest
Step-by-step explanation:
. You have that:
- The homeowner want the length of the swimming pool to be 4 feet longer than its width.
- He wants to surround it with a concrete walkway 3 feet wide.
- He can only afford 300 square feet of concrete for the walkway.
2. Therefore, the tota area is:
At=L2xW2
L2 is the lenght of the walkway (L2=L1+3+3⇒L2=(W1+4+6)⇒L2=W1+10).
W2 is the width of the walkway (W1+3+3⇒W2=W1+6)
3. The area of the walkway is:
A2=At-A1
A2=300 ft²
4. Therefore, you have that the width of the swimming pool is:
A2=(W1+10)(W1+6)-(W1+4)(W1)
300=(W1²+6W1+10W1+60)-(W1²+4W1)
W1²+16W1+60-W1²-4W1-300=0
12W1-240=0
W1=240/12
W1=20 ft
5. And the length is:
L1=W1+4
L1=20+4
L1=24 ft
Answer:
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Step-by-step explanation:
Hope it helps
Answer:
10 inches
Step-by-step explanation:
Surface Area = π R² + π R L [ L is Slant Height ]
200 π = π (10)² + π (10) L
200 π = π (100) + π (10) L
200 π - 100 π = 10 π L
100 π = 10 π L
100 π / 10 π = L
10 = L
L = 10 inches
Hope this Helps......
Laim descended 5,050.25 feet and his elevation changed by -5,050.25.
