Answer:
if the bottom the RST equals 114 you judt need to subtract 114 from 72 and you get 42 :) sorry if it wrong
Step-by-step explanation:
Answer:
384, 216, 290, 192, 384
1446, 1 roll
Step-by-step explanation:
For rectangular boxes, calculate the sum of each side, then multiply it by two.
Box 1: 2(18 x 5) + 2(18 x 4) + 2(5 x 4) = 364
Box 3: 2(11 x 8) + 2(8 x 3) + 2(3 x 11) = 290
Box 5 is a cube (all sides equal), so you can find 1 side's area and multiply it by 6.
Box 5: 6(8 x 8) = 384
For triangular boxes, calculate the edges, then find the triangular area using area = 0.5(base x height).
Box 2: (15 x 3) + (9 x 3) + (12 x 3) + 2(0.5)(9 x 12) = 216
Box 4: 2(13 x 2) + (10 x 2) + 2(0.5)(10 x 12) = 192
Total: 364 + 290 + 384 + 216 + 192 = 1446
Rolls of wrapping paper:
Area of 1 roll = 30 x 60 = 1800
Since 1446 is less than 1800, you only need 1 roll of wrapping paper.
Answer:
x^2 + y^2 + 16x + 6y + 9 = 0
Step-by-step explanation:
Using the formula for equation of a circle
(x - a)^2 + (y + b)^2 = r^2
(a, b) - the center
r - radius of the circle
Inserting the values given in the question
(-8,3) and r = 8
a - -8
b - 3
r - 8
[ x -(-8)]^2 + (y+3)^2 = 8^2
(x + 8)^2 + (y + 3)^2 = 8^2
Solving the brackets
( x + 8)(x + 8) + (y +3)(y+3) = 64
x^2 + 16x + 64 + y^2 + 6y + 9 = 64
Rearranging algebrally,.
x^2 + y^2 + 16x + 6y + 9+64 - 64 = 0
Bringing in 64, thereby changing the + sign to -
Therefore, the equation of the circle =
x^2 + y^2 + 16x + 6y + 9 = 0
