3 years ago

Need help with this similarity question

Mathematics

1 answer:

baherus [9]3 years ago

8 0

Answer:

umm i think a i correct

Step-by-step explanation:

u welcome if im right

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A triangle with vertices at A(0, 0), B(0, 4), and C(6, 0) is dilated to yield a triangle with vertices at A′(0, 0), B′(0, 10), a

Temka [501]

K · ( 0, 0 ) = ( 0 , 0 )
k · ( 0 , 4 ) = ( 0 , 10 )
k · ( 6, 0 ) = ( 15, 0 )
k = 15/6 = 10/4 = 2.5
The answer would be: 2.5

8 0

4 years ago

5^9 · 5^3 = AH) 5^6 AH) 5^-6 AH) 5^12 AH) 5^3

Temka [501]

Answer:

5´12

Step-by-step explanation:

same base 5

9+3=12

5'12

5 0

3 years ago

PLEASE HELP I NEED TO DO THIS BUT I DON’T KNOW HOW

galben [10]

Here is the answer but you didnt helped me to give a quadrilateral for solving according to my assummance i have done it if solution is ok then only give brainlest if it is wrong then re,ove the answer

7 0

3 years ago

Find the value of x 4=5x-3

Artemon [7]

4=5x-3
4+3 = 5x
7 = 5x
x = 1.4

5 0

4 years ago

Read 2 more answers

The area of a circle (A) is given by the formula A=r^2 where r is the circle's radius. The formula to find r is______ . If (A)=5

9966 [12]

Answer: (A) and (A)

Step-by-step explanation:

$A=\pi \cdot r^2\\\\\dfrac{A}{\pi}=r^2\\\\\sqrt{\dfrac{A}{\pi}}=r\ \rightarrow \ \bigg(\dfrac{A}{\pi}\bigg)^{\dfrac{1}{2}}\\\\\\\\r=\sqrt{\dfrac{A}{\pi}}\\\\.\ =\sqrt{\dfrac{54\cdot 7}{22}}\\\\.\ =\sqrt{\dfrac{27\cdot 7}{11}}\\\\.\ =\sqrt{\dfrac{189}{11}}\\\\.\ =\sqrt{17.1818}\\\\.\ =4.15$

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3 years ago