The area of a circular sector of central angle α (in radians) in a circle of radius r is given by
... A = (1/2)r²×(α - sin(α))
Your area is expected to be computed as the sum of the areas of a sector with angle π/3 in a circle of radius 8 and a sector with angle π/2 in a circle of radius 6.
... A = (1/2)8²×(π/3 - sin(π/3)) + (1/2)6²×(π/2 - sin(π/2))
... A ≈ 16.07
Radii are in inches so the units of area will be in². The appropriate choice is
... 16.10 in²
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It should be noted that the geometry described is impossible. Chord CD of circle A will have length 6√2 ≈ 8.4853 inches. Chord CD of circle B will have length 8 inches. They cannot both be the same chord.
Answer:
The one-fourth of one round of cheddar cheese
Step-by-step explanation:
Because if we cut every round in 4 equal pieces, 4x3=12, we will have 12 equal pieces of cheddar cheese.
Plug y=-5 into the equation
6x+8(-5)=-22
6x-40=-22
6x=-22+40
6x=18
x=3
After manipulating above equation we get, 2x^2 - 7x - 8= 0. Discriminant= b^2 - 4ac = (-7)^2 - 4(2)(-8) = 113>0. So there are 2 real roots :)
It's name is “isosceles triangle”
