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Rina8888 [55]
3 years ago
9

An archeologist discovered two artifacts buried beneath the ground. She found the first artifact at an elevation of -8:2/7 meter

s and the second at an elevation of 35:4/7 meters. What is the distance between these two elevations?
A) -43:6/7
B) -27:2/7
C) 27:2/7
D) 43:6/7
Mathematics
2 answers:
8090 [49]3 years ago
5 0

Answer:

Option D is the correct choice.

Step-by-step explanation:

We are provided angle of elevations of two artifacts buried beneath the ground and we are asked to find distance between these two elevations.

We will find distance between these elevations by taking the difference of two.

35:\frac{4}{7}--8:\frac{2}{7}

35:\frac{4}{7}+8:\frac{2}{7}=43:\frac{6}{7}

Since we know that distance is always positive so option A is incorrect.

Therefore, option D is the correct choice and distance between these two elevations is 43:\frac{6}{7}.

Gelneren [198K]3 years ago
3 0

Answer:

The correct option is D.

Step-by-step explanation:

It is given that an archaeologist discovered two artifacts buried beneath the ground.

Elevation of first artifact = -8\frac{2}{7}

Elevation of second artifact = 35\frac{4}{7}

We need to find the distance between these two elevations.

Distance = Elevation of first artifact - Elevation of second artifact

Distance=-8\frac{2}{7}-(35\frac{4}{7})

Distance=-(8+\frac{2}{7})-(35+\frac{4}{7})

Distance=-8-\frac{2}{7}-35-\frac{4}{7}

On further simplification we get

Distance=-43-\frac{6}{7}

Distance=-(43+\frac{6}{7})

Distance=-43\frac{6}{7}

Distance can not be negative. So, find the absolute value.

Distance=|-43\frac{6}{7}|

Distance=|43\frac{6}{7}|

Therefore, the correct option is D.

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\green{\large\underline{\sf{Solution-}}}

<u>Given expression is </u>

\rm :\longmapsto\:\dfrac{5 \times  {25}^{n + 1}  - 25 \times  {5}^{2n} }{5 \times  {5}^{2n + 3}  -  {25}^{n + 1} }

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\purple{\rm :\longmapsto\:\boxed{\tt{  {( {x}^{m} )}^{n}  \: = \:   {x}^{mn}}}} \\

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\purple{\rm :\longmapsto\:\boxed{\tt{ \:  \:   {x}^{m} \times  {x}^{n} =  {x}^{m + n} \: }}} \\

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\rm \:  =  \: \dfrac{5 \times  {5}^{2n + 2}  - {5}^{2n + 2} }{{5}^{2n + 3 + 1}  -  {5}^{2n + 2} }

\rm \:  =  \: \dfrac{{5}^{2n + 2 + 1}  - {5}^{2n + 2} }{{5}^{2n + 4}  -  {5}^{2n + 2} }

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\rm \:  =  \: \dfrac{{5}^{2n + 2 + 1}  - {5}^{2n + 2} }{{5}^{2n + 2 + 2}  -  {5}^{2n + 2} }

\rm \:  =  \: \dfrac{ {5}^{2n + 2} (5 - 1)}{ {5}^{2n + 2} ( {5}^{2}  - 1)}

\rm \:  =  \: \dfrac{4}{25 - 1}

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\rm \:  =  \: \dfrac{1}{6}

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\rm :\longmapsto\:\boxed{\tt{ \dfrac{5 \times  {25}^{n + 1}  - 25 \times  {5}^{2n} }{5 \times  {5}^{2n + 3}  -  {25}^{n + 1} }  =  \frac{1}{6} }}

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