Question

Using the given equation find the missing coordinates of the points and then find the slope of the line for each equation y= 0.3x + 1; A(...;9), B(5;...) The slope is

Answer 1

Answer:

$A = (\frac{80}{3},9)$

$B = (5,2.5)$

The slope is 0.3

Step-by-step explanation:

Given

$y = 0.3x + 1$

$A = (-,9)$

$B = (5,-)$

Required:

Fill in the gap and calculate the slope

In $A = (-,9)$

$y = 9$ and x is ??

Substitute 9 for y in $y = 0.3x + 1$

$9 = 0.3x + 1$

Collect Like Terms

$0.3x = 9 - 1$

$0.3x = 8$

$x = \frac{8}{0.3}$

$x = \frac{80}{3}$

So:

$A = (-,9)$

$A = (\frac{80}{3},9)$

In $B = (5,-)$

$x = 5$ and y is ??

Substitute 5 for x in $y = 0.3x + 1$

$y = 0.3 * 5 + 1$

$y = 1.5 + 1$

$y = 2.5$

So:

$B = (5,-)$

$B = (5,2.5)$

Calculating the slope (m)

$m = \frac{y_2 - y_1}{x_2 - x_1}$

$m = \frac{2.5-9}{5 - \frac{80}{3}}$

$m = \frac{-6.5}{\frac{15- 80}{3}}$

$m = \frac{-6.5}{\frac{-65}{3}}$

$m = \frac{-6.5*3}{-65}$

$m = \frac{-19.5}{-65}$

$m = 0.3$