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yawa3891 [41]
3 years ago
8

1 ⅕ - ⅓ = ? Please I need help--

Mathematics
2 answers:
ASHA 777 [7]3 years ago
6 0
The answer is 13/15 hope this helps
Sunny_sXe [5.5K]3 years ago
3 0
1 1/5 - 1/3
6/5-1/3
18/15-5/15
13/15 is your answer.
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Solve for t in d = rt , if d = 57 and r = 30 t = ?
bulgar [2K]

Answer:

1.9

Step-by-step explanation:

First step would be to separate r from t

\frac{d}{r}  = t

Then just insert the numbers

\frac{57}{30}  = 1.9

6 0
4 years ago
Find the solution r(t)r(t) of the differential equation with the given initial condition: r′(t)=⟨sin9t,sin6t,9t⟩,r(0)=⟨4,6,3⟩
klemol [59]

\mathbf r'(t)=\langle\sin9t,\sin6t,9t\rangle


\mathbf r(t)=\displaystyle\int\mathbf r'(t)\,\mathrm dt


\mathbf r(t)=\left\langle\displaystyle\int\sin9t\,\mathrm dt,\int\sin6t\,\mathrm dt,\int9t\,\mathrm dt\right\rangle


\displaystyle\int\sin9t\,\mathrm dt=\frac19\cos9t+C_1

\displaystyle\int\sin6t\,\mathrm dt=\frac16\cos6t+C_2

\displaystyle\int9t\,\mathrm dt=\frac92t^2+C_3


With the initial condition \mathbf r(0)=\langle4,6,3\rangle, we find


\dfrac19\cos0+C_1=4\implies C_1=\dfrac{35}9

\dfrac16\cos0+C_2=6\implies C_2=\dfrac{35}6

\dfrac92\cdot0^2+C_3=3\implies C_3=3


So the particular solution to the IVP is


\mathbf r(t)=\left\langle\dfrac19\cos9t+\dfrac{35}9,\dfrac16\cos6t+\dfrac{35}6,\dfrac92t^2+3\right\rangle

4 0
3 years ago
What is the period of the function?
blsea [12.9K]

Answer:

2pi

Step-by-step explanation:

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3 years ago
Expression z divide by 5 then add 3
DaniilM [7]

Answer:

x

5

Step-by-step explanation:

First choose a variable to represent the number,

Let's call it

x

We need to divide that number by

5

x

÷

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or

x

5

is how you write it as an expression.

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3 years ago
What is the value of h?
nekit [7.7K]

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10ft

Step-by-step explanation:

3 0
3 years ago
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