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vladimir2022 [97]
2 years ago
12

1/3 cubed = ???? what​

Mathematics
2 answers:
Sedaia [141]2 years ago
5 0

Answer:

1/27

Step-by-step explanation:

1/3 ^3 is 1.27

You take 1 ^3= 1

And 3^3 = 27

and make it 1/27

Ulleksa [173]2 years ago
4 0

Answer:

1/27

plz mark brainest

Step-by-step explanation:

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Two families are shopping for a camping trip. The first family buys 3 flashlights and 4 sleeping bags at a cost of $118. The sec
Sliva [168]

Answer:

3x +4y = 118

5x+6y =180

y= $25

Step-by-step explanation:

Let x = the cost of a flashlight

Let y = the cost of a sleeping bag

3x +4y = 118

5x+6y =180

Multiply the first equation by -5

-5(3x +4y) = -5*118

-15x -20y = -590


Multiply the second equation by 3

3(5x+6y) =3*180

15x + 18y = 540

Add the modified equations together.

We are using elimination to eliminate the variable x

-15x -20y = -590

15x + 18y = 540

----------------------------

-2y = -50

Divide by -2

-2y/-2 = -50/-2

y =25

Each sleeping bag costs $25

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2 years ago
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Answer:

D is the right answer right

Step-by-step explanation:

D

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3 years ago
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Why does nobody talk to circles?
valina [46]

why does nobody talk to circles? :3

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I^8+i^9+i^10 PLZ EXPLAIN HOW YOU GET THE ANSWER
NeX [460]
<span>I^8+i^9+i^10 PLZ EXPLAIN HOW YOU GET THE ANSWER

</span>i^0= 1\qquad i^1= i\qquad i^2= -1 \qquad i^3= -i \\  \\  \\ i^8= i^3*i^3*i^2 \\  \\ i^8= -i*-i*1\to i^8= i^2*1 \to \qquad  \boxed{i^8= 1} \\  \\  \\ i^9= i^3*i^3*i^3 \\  \\ i^9= -i*-i*-i\to i^9= i^2*(-i)\qquad  \boxed{i^9= -i}  \\  \\  \\ i^1^0= i^3*i^3*i^3*i \\  \\ i^1^0= -i*-i*-i*i\to i^1^0= i^2*(-i^2)\to -1*1\qquad  \boxed{i^1^0= -1}  \\  \\  \\ i^8+i^9+i^1^0= (1)+(-i)+(-1)=  \boxed{-i}
<span>
</span>\boxed{ i^8+i^9+i^1^0=  \boxed{-i} }<span>

</span>
7 0
3 years ago
B is the midpoint ofAC, AB = 4x – 2,<br> BC = 2x + 4. Find the lengths of AB,BC and AC.
Pachacha [2.7K]

if B is the midpoint of AC, that means that B cuts AC in two equal halves, namely  that AB and BC are identical twins.

\bf \boxed{A}\stackrel{4x - 2}{\rule[0.35em]{10em}{0.25pt}} B\stackrel{2x+4}{\rule[0.35em]{10em}{0.25pt}}\boxed{C} \\\\\\ 4x - 2 = 2x + 4\implies 2x-2=4\implies 2x = 6\implies x=\cfrac{6}{2}\implies x = 3 \\\\[-0.35em] ~\dotfill\\\\ \stackrel{AB~=~BC}{4(3)-2= \underline{10}}~\hfill \stackrel{AC = AB+BC}{\underline{10}+\underline{10}=20}

6 0
3 years ago
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